更好的方式将NSArray的NSNumbers转换为NSStrings数组 [英] Better way to convert NSArray of NSNumbers to array of NSStrings

问题描述

我有一个 NSArray 由 NSNumbers 组成，我想将其转换为通过获取每个 NSNumber的 stringValue ，获得 NSStrings 的NSArray 。

I have an NSArray consisting of NSNumbers and I want to convert this to an NSArray of NSStrings, by getting the stringValue of each NSNumber in the first array.

我想到的方法是迭代第一个值中的每个值，获取其字符串值并将其添加到另一个数组中。但是应该有一个更优雅的解决方案。你知道吗？

The method that comes to my mind is iterating each value in the first one, getting its string value and adding it into another array. But there should be a more elegant solution for this. Do you know one?

推荐答案

NSArray http://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Protocols/NSKeyValueCoding_Protocol/Reference/Reference.html%23//apple_ref/occ/cat/NSKeyValueCoding\">关键字编码方法 valueForKey： ，以便返回一个新数组。新数组包含查询原始数组中每个对象的指定值的结果。在这种情况下， NSNumber 有它的 stringValue ，所以你需要做的是：

NSArray implements the Key-Value Coding method valueForKey: in such a way that it returns a new array. The new array contains the results of asking each object in the original array for the specified value. In this case, NSNumber has its stringValue, so all you have to do is:

NSArray * b = [a valueForKey:@"stringValue"];

普通旧的快速枚举（或 enumerateObjectsUsingBlock： ）不会是一个可怕的解决方案，但。 NSArray 的实施 valueForKey：最有可能使用 for 循环内部，这将是很容易被任何人谁读它后来很容易理解。

Plain old fast enumeration (or enumerateObjectsUsingBlock:) wouldn't be a terrible solution, though. NSArray's implementation of valueForKey: most likely uses a for loop internally, and that would be pretty readily understood by anyone who reads it later.

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