iOS如何实现协议的@property [英] iOS how to implement a protocol's @property

问题描述

我的理解是协议指定方法名称，并且符合该协议的其他人执行方法。

What I understand is that a protocol specify method names, and someone else who conforms to that protocol do the implementation of the methods.

那么在协议中声明的属性呢？是实现一个属性意味着实现它的setter和getter？

So what about the properties declared in a protocol? Is that to implement a property means to implement its setter and getter?

推荐答案

属性是一个或两个具有特定签名的方法的奇特名称，为此Objective-C提供一个约定，他们使用替代点。语法。一个协议声明，例如一对

Property is a fancy name for one or two methods with specific signatures for which Objective-C provides a convention that lets you call them using the alternative dot . syntax. There is no difference between a protocol declaring, say, a pair of

-(int) foo;
-(void)setFoo:(int)_foo;

方法和协议声明读写属性：

methods, and a protocol declaring a read-write property:

 @property (readwrite) foo;

所以你是绝对正确的，实现一个属性意味着实现一个或两个方法，只读，只写或读写属性。

So you are absolutely right, implementing a property means implementing one or two methods, depending on whether you implement a read-only, write-only, or a read-write property.

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