什么是& >平均/代表在类接口？ [英] What does < > mean / represent in a class interface?

问题描述

我相信我已经读过这个地方，任何人都可以告诉我什么< >代表在下面的界面？

  @interface GameFinder：NSObject< NSNetServiceBrowserDelegate> NSobserverBrowserDelegate>< NSNetServiceBrowserDelegate>     code>？
 
 
 
 EDIT 
 
 
 
有一件事让我感到困惑... 
界面显示 NSNetServiceBrowserDelegate  
  @interface ITunesFinder：NSObject< NSNetServiceBrowserDelegate> 
 @end 
  
但实施显示 netServiceBrowser 一个在同一个？
  @implementation ITunesFinder 
  - （void）netServiceBrowser：（NSNetServiceBrowser *）browser 
 didFindService：（NSNetService *）service 
 moreComing：（BOOL）moreComing {
  
 
 
 
解决方案
尖括号表示此类遇到的协议。有关 Objective-C维基百科文章中的协议的详细信息，可能有助于清除给你一些东西。协议包含您的类可以提供的必需和可选例程。在后一种情况下，如果例程不是由您的类实现，则使用默认实现/行为。
 
I am sure I have read this somewhere, Can anyone tell me what the < > represent in the following interface?
@interface GameFinder : NSObject <NSNetServiceBrowserDelegate>
@end
is NSObject adopting <NSNetServiceBrowserDelegate> ?

EDIT

One thing that is confusing me ...

in the example I have.The interface shows NSNetServiceBrowserDelegate
@interface ITunesFinder : NSObject <NSNetServiceBrowserDelegate>
@end
but the implementation shows netServiceBrowser, are these one in the same?
@implementation ITunesFinder
-(void) netServiceBrowser: (NSNetServiceBrowser *) browser
           didFindService: (NSNetService *) service
               moreComing: (BOOL) moreComing {
gary
解决方案
The angle brackets denote Protocols that this class meets. There are details on Protocols int the Objective-C Wikipedia article that may help clear up some things for you. Protocols contain both required and optional routines that your class could supply. In the latter case if the routine is not implemented by your class a default implementation/behavior is used instead.

                        
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