计算可可中的目录大小 [英] calculating directory size in cocoa

问题描述

我想计算目录（文件夹）大小，我必须列出所有的文件和文件夹（子文件夹）在一个卷（驱动器）与其相应的大小。我使用下面的代码来计算大小。这个问题代码是性能问题。我使用 NSBrowser 显示。

  NSArray * filesArray = [[ NSFileManager defaultManager] subpathsOfDirectoryAtPath：folderPath error：nil]; 
 NSEnumerator * fileEnumerator = [filesArray objectEnumerator]; 
 NSString * fileName; 
 unsigned long long int fileSize = 0; 
 
 while（fileName = [filesEnumerator nextObject]）
 {
 NSDictionary * fileDictionary = [[NSFileManager defaultManager] attributesOfItemAtPath：folderPath error：nil]; 
 fileSize + = [fileDictionary fileSize]; 
} 
 
 return fileSize; 
  

问题：

p>谢谢...

解决方案

您可以使用 stat 。

   - （unsigned long long）getFolderSize：（NSString *）folderPath; 
 
 {
 char * dir =（char *）[folderPath fileSystemRepresentation]; 
 DIR * cd; 
 
 struct dirent * dirinfo; 
 int lastchar; 
 struct stat linfo; 
 static unsigned long long totalSize = 0; 
 
 cd = opendir（dir）; 
 
 if（！cd）{
 return 0; 
} 
 
 while（（dirinfo = readdir（cd））！= NULL）{
 if（strcmp（dirinfo-> d_name，。）&& strcmp（dirinfo-> d_name，..））{
 char * d_name; 
 
 
 d_name =（char *）malloc（strlen（dir）+ strlen（dirinfo-> d_name）+2）; 
 
 if（！d_name）{
 //内存不足
 closedir（cd）; 
 exit（1）; 
} 
 
 strcpy（d_name，dir）; 
 lastchar = strlen（dir） -  1; 
 if（lastchar> = 0& dir [lastchar]！='/'）
 strcat（d_name，/）; 
 strcat（d_name，dirinfo-> d_name）; 
 
 if（lstat（d_name，& linfo）== -1）{
 free（d_name）; 
 continue; 
} 
 if（S_ISDIR（linfo.st_mode））{
 if（！S_ISLNK（linfo.st_mode））
 [self getFolderSize：[NSString stringWithCString：d_name encoding：NSUTF8StringEncoding] ]; 
免费（d_name）; 
} else {
 if（S_ISREG（linfo.st_mode））{
 totalSize + = linfo.st_size; 
} else {
 free（d_name）; 
} 
} 
} 
} 
 
 closedir（cd）; 
 
 return totalSize; 
 
} 
  

查看 Mac OS X无法正确报告目录大小

I want to calculate the directory (folder)size and i have to list all files and folders (subfolders) in a volume(drive) with its corresponding size.I am using the below code to calculate size.The problem with this code is the performance issue . I am using NSBrowser to display .

NSArray *filesArray = [[NSFileManager defaultManager] subpathsOfDirectoryAtPath:folderPath error:nil];
NSEnumerator *filesEnumerator = [filesArray objectEnumerator];
NSString *fileName;
unsigned long long int fileSize = 0;

while (fileName = [filesEnumerator nextObject]) 
{
    NSDictionary *fileDictionary = [[NSFileManager defaultManager] attributesOfItemAtPath:folderPath error:nil];
    fileSize += [fileDictionary fileSize];
}

return fileSize;

Questions:

1. Is there any built in function available?

2. If not what is the best way to calculate the size?

3. Is it good to use cache to store already calculated file size?

Thanks...

解决方案

You can use stat.

-(unsigned long long)getFolderSize : (NSString *)folderPath;

{
    char *dir = (char *)[folderPath fileSystemRepresentation];
DIR *cd;

struct dirent *dirinfo;
int lastchar;
struct stat linfo;
static unsigned long long totalSize = 0;

cd = opendir(dir);

if (!cd) {
    return 0;
}

while ((dirinfo = readdir(cd)) != NULL) {
    if (strcmp(dirinfo->d_name, ".") && strcmp(dirinfo->d_name, "..")) {
        char *d_name;


        d_name = (char*)malloc(strlen(dir)+strlen(dirinfo->d_name)+2);

        if (!d_name) {
            //out of memory
            closedir(cd);
            exit(1);
        }

        strcpy(d_name, dir);
        lastchar = strlen(dir) - 1;
        if (lastchar >= 0 && dir[lastchar] != '/')
            strcat(d_name, "/");
        strcat(d_name, dirinfo->d_name);

        if (lstat(d_name, &linfo) == -1) {
            free(d_name);
            continue;
        }
        if (S_ISDIR(linfo.st_mode)) {
            if (!S_ISLNK(linfo.st_mode))
                [self getFolderSize:[NSString stringWithCString:d_name encoding:NSUTF8StringEncoding]];
            free(d_name);
        } else {
            if (S_ISREG(linfo.st_mode)) {
                totalSize+=linfo.st_size;
            } else {
                free(d_name);
            }
        }
    }
}

closedir(cd);

return totalSize;

}

Take a look at Mac OS X not reporting directory sizes correctly?

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