ASIFormDataRequest + PHP问题 [英] ASIFormDataRequest + PHP Issues

问题描述

我尝试使用ASIFormDataRequest将文件上传到服务器（从自定义mac os应用程序）。在我的可可/ obj-c代码中，我有：

I'm trying to upload a file to a server (from a custom mac os application) using ASIFormDataRequest. In my cocoa/obj-c code, I have:

- (IBAction)uploadFile:(id)sender 
{ 
 [networkQueue reset];
 [networkQueue setShowAccurateProgress:YES];
 [networkQueue setUploadProgressDelegate:progressIndicator];
 [networkQueue setRequestDidFailSelector:@selector(postFailed:)];
 [networkQueue setRequestDidFinishSelector:@selector(postFinished:)];
 [networkQueue setDelegate:self];

 ASIFormDataRequest *request = [[[ASIFormDataRequest alloc] initWithURL:[NSURL URLWithString:@"http://domain.com/to/upload.php"]] autorelease];

 [request setFile:@"/path/to/file.jpg" forKey:@"file"];

 [networkQueue addOperation:request];
 [networkQueue go];

}

- (void)postFinished:(ASIHTTPRequest *)request
{
 NSLog(@"Post Success");
}
- (void)postFailed:(ASIHTTPRequest *)request
{
 NSLog(@"Post Failed");
}

服务器上的PHP代码如下：

The PHP code on the server looks like this:

$target_path = "files/";

$target_path = $target_path . basename( $_FILES['uploadedfile']['name']); 

if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
  echo "The file ".  basename( $_FILES['uploadedfile']['name']). 
    " has been uploaded";
 } else{
  echo "There was an error uploading the file, please try again!";
 }

当我尝试使用此代码上传文件时，成功响应，但文件从未显示在我的服务器上。我有CHMODed文件文件夹到777，以防万一，但它仍然没有工作。有没有人有建议，或看到我接近这个错误？

When I try to upload a file using this code, I get a "Post Success" response on the client end, but the file never shows up on my server. I have CHMODed the files folder to 777 just in case, but it still didn't seem to work. Does anyone have a suggestion, or see an error in the way I'm approaching this?

谢谢！

推荐答案

更新未来读者 。这里的根本问题是你必须像下面这样创建ASIFormDataRequest项：

Update for future readers. The fundamental problem here was that you must create ASIFormDataRequest items exactly like this:

NSURL *url = [NSURL URLWithString:@"https://www.you.com/cgi-bin/you.cgi?stuff"];
ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];

不要 保留，自动释放，自我等。就是这样。

Do not add in more release, retain, autorelease, self., etc etc! That's all it is.

嗯。我不完全确定autorelease有正确。你必须小心不要在ASIHttpRequest中丢失resuest指针。

Hmm. I'm not entirely sure the autorelease there is correct. You have to be careful about not losing resuest pointers in ASIHttpRequest.

设置一下，它是值得尝试它作为一个简单的（非排队，异步）请求，使用已被测试过几十亿次的这种模式：

Setting that aside, would it be worth trying it first as a simple (non-queued, asynchronous) request, using exactly this pattern which has been tested billions of times:

-(void) sendSomethingAnything
    {
    NSURL *url = [NSURL URLWithString:@"https://www.you.com/cgi-bin/you.cgi?stuff"];
    ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];

    [request setPostValue:@"fakeIDstring" forKey:@"id"];
    [request setPostValue:@"anotherCalue" forKey:@"username"];
    // your file here ..

    [request setDelegate:self];
    [request setDidFinishSelector:@selector(postFinished:)];
    [request setDidFailSelector:@selector(postFailed:)];

    [request startAsynchronous];
    }

只需粘贴到您的网址，您可以立即尝试。这将消除很多问题，让我们更接近的问题。在done例程中，获取并显示结果像这样...

Just paste in your URL and you can try that immediately. That will eliminate a lot of problems and get us closer to the problem. In the done routine, get and show the result like this...

NSData *newStringData = [request responseData];
NSString *x = [[[NSString alloc] initWithData:newStringData
                  encoding:NSUTF8StringEncoding] autorelease];
NSLog(@"result text from server is %@", x);

最后在您的PHP。我发现添加一行代码，EMAILS ME从PHP，说明什么是发生有用的。或者，使用wall命令，并且只有在您使用客户端时在您的服务器上打开一个shell。

Finally in your PHP. I find it useful to add a line of code that EMAILS ME from the php stating what the heck is going on. Alternately, use a "wall" command, and just have a shell open on your server as you work with the client. It's the only way to see what the heck is going on as you work.

（实际上我使用的是老式的perl，而不是未来派的php，所以我不能提供任何代码！））

(In fact I use old-fashioned perl rather than futuristic php, so I can't offer any code on that end! :) )

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