上传文件骨干力量tastypie? [英] Uploading files to tastypie with Backbone?
问题描述
经过一些其他的问题,我想我的tastypie资源应该是这个样子:
Checked some other questions and I think my tastypie resource should look something like this:
class MultipartResource(object):
def deserialize(self, request, data, format=None):
if not format:
format = request.META.get('CONTENT_TYPE', 'application/json')
if format == 'application/x-www-form-urlencoded':
return request.POST
if format.startswith('multipart'):
data = request.POST.copy()
data.update(request.FILES)
return data
return super(MultipartResource, self).deserialize(request, data, format)
class ImageResource(MultipartResource, ModelResource):
image = fields.FileField(attribute="image")
请告诉我,如果这是错误的。
Please tell me if that's wrong.
我不明白是什么,假设以上是正确的,是要传递给资源。下面是一个文件输入:
What I don't get, assuming the above is correct, is what to pass to the resource. Here is a file input:
<input id="file" type="file" />
如果我有一个主干模型IMG做什么我设置图像?
If I have a backbone model img what do I set image to?
img.set("image", $("#file").val()); // tastypie doesn't store file, it stores a string
img.set("image", $("#file").files[0]); // get "{"error_message": "'dict' object has no attribute '_committed'" ...
怎么设置我的脊梁图像属性,这样我可以上传文件通过AJAX来tastypie?
What do I set my backbone "image" attribute to so that I can upload a file to tastypie via ajax?
推荐答案
您可以覆盖同步
方法 FORMDATA $ C $连载C> API,以便能够提交文件,模型的属性。
You may override sync
method to serialize with FormData
api to be able to submit files as model's attributes.
请注意,它会在现代浏览器只工作。它曾与骨干0.9.2,我建议要检查默认Backbone.sync,并据此通过的想法。
Please note that it will work only in modern browsers. It worked with Backbone 0.9.2, I advise to check the default Backbone.sync and adopt the idea accordingly.
function getValue (object, prop, args) {
if (!(object && object[prop])) return null;
return _.isFunction(object[prop]) ?
object[prop].apply(object, args) :
object[prop];
}
var MultipartModel = Backbone.Model.extend({
sync: function (method, model, options) {
var data
, methodMap = {
'create': 'POST',
'update': 'PUT',
'delete': 'DELETE',
'read': 'GET'
}
, params = {
type: methodMap[method],
dataType: 'json',
url: getValue(model, 'url') || this.urlError()
};
if (method == 'create' || method == 'update') {
if (!!window.FormData) {
data = new FormData();
$.each(model.toJSON(), function (name, value) {
if ($.isArray(value)) {
if (value.length > 0) {
$.each(value, function(index, item_value) {
data.append(name, item_value);
})
}
} else {
data.append(name, value)
}
});
params.contentType = false;
params.processData = false;
} else {
data = model.toJSON();
params.contentType = "application/x-www-form-urlencoded";
params.processData = true;
}
params.data = data;
}
return $.ajax(_.extend(params, options));
},
urlError: function() {
throw new Error('A "url" property or function must be specified');
}
});
这是从上传的观点摘录,我用&LT;输入类型=文件名称=文件多&GT;
文件上传,以便用户可以选择多个文件。后来我听的变化事件,并使用 collection.create
来上载每个文件。
This is excerpt from upload view, I use <input type="file" name="file" multiple>
for file uploads so user can select many files. I then listen to the change event and use collection.create
to upload each file.
var MultipartCollection = Backbone.Collection.extend({model: MultipartModel});
var UploadView = Backbone.View.extend({
events: {
"change input[name=file]": "changeEvent"
},
changeEvent: function (e) {
this.uploadFiles(e.target.files);
// Empty file input value:
e.target.outerHTML = e.target.outerHTML;
},
uploadFiles: function (files) {
_.each(files, this.uploadFile, this);
return this;
},
uploadFile: function (file) {
this.collection.create({file: file});
return this;
}
})
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