截断从特定字符开始的NSString的一部分 [英] Truncate part of an NSString starting at a particular character

问题描述

我有一个字符串

NSString * myOldString = @"This is a string (and this part is between brackets)"

现在，我想以这样的方式截断字符串，括号，被截断。

Now, I want to truncate the string in such a way, that basically everything between the brackets, including the brackets, is truncated.

更确切地说：我不在乎第一个括号之后发生了什么。

More precisely: I don't care what is happening after the first bracket at all.

我不能做一个简单的 stringByReplacingOccurrencesOfString：，因为我不能预测括号之间将是什么。所以，结果字符串应该是：

I can't do a simple stringByReplacingOccurrencesOfString:, because I cannot predict what will be between the brackets. So, the resulting string should be:

"This is a string"

推荐答案

一种方法：

NSArray *components = [myOldString componentsSeparatedByString:@"("];
NSString *newString = [components objectAtIndex:0];

应该也适用于没有'（'

Should also work for the case where there isn't a '('

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