“不完全通用字符名称”与stringWithUTF8String [英] "incomplete universal character name" with stringWithUTF8String

问题描述

<$ p> NSString * s = [NSString stringWithUTF8String： \U0627\U0644\U0641\U0631\U0646];
NSLog（@％@，s）;


我得到编译错误：

 不完整的通用字符名称
  

注意，它有时工作正常：

  NSString * UAE = [NSString stringWithUTF8String：\U0627\U0644\U0641\U0631\U0646] ; 
 NSLog（@％@，UAE）; 
  

和输出：

 الامارات
  

请帮助。

解决方案

\U和\u不是一回事。 \U转义需要8（十六进制）数字而不是4。

这应该工作：

  NSString * s = [NSString stringWithUTF8String：\\\ا\\\ل\\\ف\\\ر\\\ن]; 
  

when i try to convert form utf-8 string to NSString like so:

NSString *s = [NSString stringWithUTF8String:"\U0627\U0644\U0641\U0631\U0646"];
NSLog(@"%@", s);

i get the compile error:

incomplete universal character name

note that it sometime just works fine:

NSString *UAE = [NSString stringWithUTF8String:"\U0627\U0644\U0641\U0631\U0646"];
    NSLog(@"%@", UAE);

and the output:

الامارات

so why is that happening? please help.

解决方案

\U and \u are not the same thing. The \U escape expects 8 (hex) digits instead of 4.

This should work:

NSString *s = [NSString stringWithUTF8String:"\u0627\u0644\u0641\u0631\u0646"];

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