当从UINavigationController子屏幕返回时，如何保持UITableView所选行？ [英] How do I maintain the UITableView selected row when returning from a UINavigationController child screen?

问题描述

我有一个UITableView的客户，其中选择行/客户。然后，用户可以在UINavigationController堆栈上推送另一个视图以添加新客户。当我弹出子屏幕并返回到UITableView时，先前选择的行不再被选中。

I have a UITableView of customers where a row/customer is selected. The user can then push another view on the UINavigationController stack to add a new customer. When I pop the child screen and return to the UITableView the previously selected row is no longer selected.

我可以重新选择viewDidAppear（）中的行，但看起来很糟糕，你可以看到取消选择和选择。

I can re-select the row in viewDidAppear() but it looks bad as you can see the deselect and the select. Is there a way to maintain the selected row when returning from the child screen?

推荐答案

我假设你使用的是表视图控制器，否则你的责任是写这个行为反正。在表视图控制器，虽然，很容易。只需添加viewDidLoad：

I assume you are using a table view controller, as otherwise it is your responsibility to write this behaviour anyway. In a table view controller, though, it's easy. Just add in viewDidLoad:

self.clearsSelectionOnViewWillAppear = NO;

这将保持行被选中，除非您手动取消选择行或用户选择表。

That will keep the row selected, unless you manually deselect the row or the user selects another row on the table.

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