CodeIgniter选择查询 [英] CodeIgniter Select Query

问题描述

我有一个简单的CodeIgniter活动记录查询来选择一个ID：

I have a simple CodeIgniter Active record query to select an ID:

$q = $this -> db
           -> select('id')
           -> where('email', $email)
           -> limit(1)
           -> get('users');

如何将上述ID分配给变量（例如$ id）
示例，

How can I assign the above ID to a variable (eg. $id) For example,

echo "ID is" . $id;

谢谢。

推荐答案

这很简单。例如，这里是我的随机代码：

Thats quite simple. For example, here is a random code of mine:

function news_get_by_id ( $news_id )
{

    $this->db->select('*');
    $this->db->select("DATE_FORMAT( date, '%d.%m.%Y' ) as date_human",  FALSE );
    $this->db->select("DATE_FORMAT( date, '%H:%i') as time_human",      FALSE );


    $this->db->from('news');

    $this->db->where('news_id', $news_id );


    $query = $this->db->get();

    if ( $query->num_rows() > 0 )
    {
        $row = $query->row_array();
        return $row;
    }

}   

您选择作为数组，以便您可以访问它：

This will return the "row" you selected as an array so you can access it like:

$array = news_get_by_id ( 1 );
echo $array['date_human'];

我也强烈建议，不链接 。总是让他们分开像我的代码，这显然是很容易阅读。

I also would strongly advise, not to chain the query like you do. Always have them separately like in my code, which is clearly a lot easier to read.

请注意，如果在from（）中指定表名称，则调用不带参数的get（）函数。

Please also note that if you specify the table name in from(), you call the get() function without a parameter.

如果您不明白，请随时问：）

If you did not understand, feel free to ask :)

这篇关于CodeIgniter选择查询的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！