回显视图页面 [英] echoing in the view page

问题描述

我试图在视图中回显我数据库的一个字段，但我收到错误：

消息：尝试获取非对象的属性

文件名：views / admin_view_report.php

行号：7

当我回显整个数组时，它工作得很好。我找不到错误。

我的控制器的一部分：

  function index（）{
 $ this-> load-> model（'viewreport'）; 
 $ data ['records'] = $ this-> viewreport-> getAllByChk（）; 
 $ this-> load-> view（'admin_view_report'，$ data）; 
} 
  

我的模型的一部分：

  function getAllByChk（）{
 $ q = $ this-> db-> get（'info'）; 
 if（$ q-> num_rows（）> 0）{
 foreach（$ q-> result_array（）as $ row）
 {
 $ data [] = $ row; 
} 
 return $ data; 
} 
} 
  

视图：

 <？php foreach（$ records as $ row）：？> 
 
<？php echo $ row-> subject; > 
 
<？php endforeach;？> 
  

如果我只打印 data ['records'] 它给出以下输出

  Array 
（
 [0] =& $ b（
 [id] => 1 
 [address] => 11 / siddeshwari 
 [area] => sid 
 [lat] =& b $ b [lng] => 21 
 [subject] => hello 
 [问题] =>大量问题
 [image] => 
 [time ] => 2011-08-11 23:49:29 
 [register_id] => 1 
 [category_id] => 1 
 [city_city_id] => 1 
 [status_status_id] => 0 
）
 
 [1] => Array 
（
 [id] => 2 
 [address ] => 134 banani 
 [area] => banai 
 [lat] => 1223 
 [lng] => 2133 
 [subject] => not working 
 [problem] => yesproblem问题问题
 [image] => 
 [time] => 2011-08-12 01:09:44 
 [register_id] => 1 
 [category_id] => 2 
 [city_city_id] => 1 
 [status_status_id] => 0 
）
 
）
  

<$ p $ c> result_array（）

$

在您的视图中：

 
 code> $ row-> subject 
  

应为：

  $ row ['subject'] 
  

$ b

如果你想要$ row为一个对象，将 result_array（）更改为 result（）。这将给你一个对象数组。

也 foreach（$ q-> result_array（）as $ row）



只是将 $ q-> result_array（）复制到 $ data 。

你不需要这样做，只需 return $ q-> result_array ）; 。

I'm trying to echo a field of my database in the view, but I'm getting the error:

Message: Trying to get property of non-object

Filename: views/admin_view_report.php

Line Number: 7

When I echo the whole array, it works just fine. I can't find what's wrong.

Part of my controller:

function index(){
    $this->load->model('viewreport');
    $data['records']=$this->viewreport->getAllByChk();
    $this->load->view('admin_view_report',$data); 
}

Part of my model:

function getAllByChk(){
    $q = $this->db->get('info');
    if ($q->num_rows()>0){
        foreach ($q->result_array() as $row)
        {
            $data[]=$row;
        }
        return $data;
    }
}

The view:

<?php  foreach($records as $row):?>

    <?php echo $row->subject; ?>

<?php endforeach;?>

If I only print data['records'] it gives the following output

Array
(
    [0] => Array
        (
            [id] => 1
            [address] => 11/siddeshwari
            [area] => sid
            [lat] => 21
            [lng] => 21
            [subject] => hello
            [problem] => lots of problem
            [image] => 
            [time] => 2011-08-11 23:49:29
            [register_id] => 1
            [category_id] => 1
            [city_city_id] => 1
            [status_status_id] => 0
        )

    [1] => Array
        (
            [id] => 2
            [address] => 134 banani
            [area] => banai
            [lat] => 1223
            [lng] => 2133
            [subject] => not working
            [problem] => yesproblem problem problem
            [image] => 
            [time] => 2011-08-12 01:09:44
            [register_id] => 1
            [category_id] => 2
            [city_city_id] => 1
            [status_status_id] => 0
        )

)

but when I try to print the problem or subject only it gives the error.

解决方案

result_array() returns you an array of arrays, not of objects.

In your view:

$row->subject

should be:

$row['subject']

If you want $row to be an object, change result_array() to result(). This will give you an array of objects.

Also foreach ($q->result_array() as $row) is redundant.

It's just copying $q->result_array() to $data.

You don't need to do that, just return $q->result_array();.

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