codeigniter相关的下拉与jquery和ajax post [英] codeigniter - dependent dropdown with jquery and ajax post

问题描述

view：learning_view.php

view : learning_view.php

这是我从数据库填充的第一个下拉列表。

Here is the first dropdown which I am populating from database.

    <select name = 'category' id = 'category'>
        <option value="">-- Select Category --</option>
        <?php foreach($category as $item){ ?>
        <option value="<?php echo $item->id_cat; ?>"><?php echo $item->name; ?></option>
        <?php } ?>
    </select>
    <br><br>

我想要的是填充另一个下拉列表，这取决于第一个下拉列表。为此，我使用了jQuery ajax post。

What I want is to populate another dropdown which is dependent on the first dropdown. For that I have used the jQuery ajax post.

第二个下拉菜单：

    <select name = 'type' id = 'type'>
        <option value="">-- Select Type --</option>
        <?php foreach($type as $item){ ?>
        <option value="<?php echo $item->id_type; ?>"><?php echo $item->name; ?></option>
        <?php } ?>
    </select>
    <br><br>

ajax post：

ajax post:

    jQuery(document).ready(function(){
      $("#category").change(function() {
        var category_id = {"category_id" : $('#category').val()};
        console.log(category_id);

        $.ajax({
          type: "POST",
          data: category_id,
          url: "<?= base_url() ?>learning/dependent_dropdown",

          success: function(data){

            $.each(data, function(i, data){
            console.log(data.name);
            console.log(data.id_type)
            });
           }
         });
       });
     });

控制器：learning.php

controller : learning.php

   public function dependent_dropdown()
   {
       if(isset($_POST['category_id']))
       {
           $this->output
           ->set_content_type("application/json")
           ->set_output(json_encode($this->learning_model->getType($_POST['category_id'])));
       }
   }

数据来自ajax post后的数据库我检查过

The data is coming from the database after ajax post which I checked by

    console.log(data.name);
    console.log(data.id_type)

但无法找出如何使用我的视图的第二个下拉列表中的数据。

But couldn't able to figure out how to use the data in the second dropdown of my view.

我的意思是我如何填充第二个下拉列表，我在ajax post后收到的数据。

I mean how can i populate the second dropdown with the data i have received after ajax post.

推荐答案

我通过修改ajax post的成功函数找到了我的问题的解决方案：

I found a solution to my problem by modifying the success function of the ajax post:

success: function(data) {
    $.each(data, function(i, data) {
        $('#type').append("<option value='" + data.id_type + "'>" + data.name + "</option>");
    });
}

将值附加到下拉菜单中。

Which append the value into the drop down.

<select name="type" id="type">
    <option value="">-- Select Type --</option>
</select>

我只是把选择块的id放到ajax post的成功函数中，并附加了值。它的工作，但有一个问题，当我更改第一个下拉选择新值出现，但显示为上一个选择的值不会消失。

I just gave the id of the select block into the success function of the ajax post and appended the value. It works but there is a problem which is when I change the selection of the first dropdown new value appears but the values which were showing for the previous selection doesn't go away.

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