最快/最干净的方式在内存中加载文本文件 [英] Fastest/Cleanest way to load a text file in memory

问题描述

我知道类似的问题以前被问过，但是我找不到能回答我确切问题的问题。

I know similar questions have been asked before, but I couldn't find one that answers my exact question.

我需要一种方法来读取文件 String 使用最少的代码，尽可能简单和最优。

I need a way to read a file as a String with the least code and as simple and as optimal as possible.

我不在找： / p>

I'm not looking for:

final BufferedReader br = new BufferedReader(new FileReader(file));
String line = null;
while ((line = br.readLine()) != null) {

  // logic
}

我知道我可以写自己的帮助类来做这个。

And I know I can write my own helper class that does this.

我在找东西更多的沿线：

I'm looking for something more along the lines of:

final String wholeFileAsStr = Something.load(file);

其中 Something.load（）

任何人都可以从Guava或Apache推荐一些我可能不知道的东西？

Can anyone recommend something from Guava or Apache maybe that I'm not aware of ?

提前感谢。

推荐答案

http://commons.apache.org/io/api-1.2/org/apache/commons/io/IOUtils.html#toString%28java.io.InputStream%29rel =nofollow> IOUtils.toString ，来自Commons IOUtils

Perhaps IOUtils.toString , from Commons IOUtils

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