简写typedef指向常量结构体的指针 [英] shorthand typedef pointer to a constant struct

问题描述

使用typedef声明结构

Declaring a struct with typedef

typedef struct some_struct {
int someValue;
} *pSomeStruct;

然后将它作为参数传递给一些带有const声明的函数，意味着'const some_struct * var'

and then passing it as a parameter to some function with const declaration, implying 'const some_struct * var'

void someFunction1( const pSomeStruct var )

原来是

some_struct * const var

这也在ISO C标准的第6.7.5.1节中说明，其中const在这种情况下适用于指针，而不是到它所指向的数据。

This is also stated in Section 6.7.5.1 of the ISO C standard which states that 'const' in this case applies to the pointer and not to the data to which it points.

所以问题是 - 有一种方法来声明一个指向const结构的指针，使用typedef的简写符号，或者必须总是一个特殊的单独声明：

So the question is - is there a way to declare a pointer to a const struct in a shorthanded notation with typedef, or there must always be a special separate declaration for it:

typedef const struct some_struct *pcSomeStruct;
void someFunction2( pcSomeStruct var )

推荐答案

，do not typedef pointers：）

Basically, do not typedef pointers :)

typedef struct some_struct {} some_struct;

void some_function1(some_struct *var);
void some_function2(const some_struct *var);
void some_function3(some_struct *const var);
void some_function4(const some_struct *const var);

---

或者，完全不要typedef：D

---

Or, don't typedef at all :D

struct some_struct {};

void some_function1(struct some_struct *var);
void some_function2(const struct some_struct *var);
void some_function3(struct some_struct *const var);
void some_function4(const struct some_struct *const var);

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