Iterable.sliding的输出为Tuple [英] Output of Iterable.sliding as Tuple

问题描述

对集合的滑动方法以X [Iterable [A]]的形式返回给定大小的滑动窗口，其中X是集合的类型，A是元素类型。通常我需要两个或三个元素，我更喜欢他们命名。滑动（2）的一个丑陋的解决方法如下：

The method sliding on collections returns a sliding window of given size in the form of X[Iterable[A]] with X being the type of the collection and A the element type. Often I need two or three elements and I prefer to have them named. One ugly workaround for sliding(2) is the following:

points.sliding(2).foreach{ twoPoints =>
      val (p1,p2) = (twoPoints.head,twoPoints.last)
      //do something
}

这吸引，只适用于两个元素。另请注意

This sucks and only works for two elements. Also note that

(a,b) = (twoPoints(0),twoPoints(1))

无法使用。帮助我！

推荐答案

我在这个答案。 / p>

I did a lot of that in this answer just last week.

points.sliding(2).foreach { case X(p1, p2) => ... }

如果 points Array ，然后用 Array 替换 X 。如果是 List ，用 List 替换 X

If points is an Array, then replace X with Array. If it is a List, replace X with List, and so on.

请注意，您正在进行模式匹配，因此您需要 {} 而不是（）作为参数。

Note that you are doing a pattern match, so you need to {} instead of () for the parameter.

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