类型不匹配错误声明类的列表 [英] type mismatch error declaring list of classes
本文介绍了类型不匹配错误声明类的列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
def getValueAndItsType() : List[ (AnyRef, Class[_]) ] = {
val dataSet1 = ("some string data", classOf[String])
val dataSet2 = (new Thread(), classOf[Thread])
val dataSet3 = (new NullPointerException(), classOf[NullPointerException])
val dataSet4 = (5, classOf[Int])
val list = List(dataSet1, dataSet2, dataSet3, dataSet4)
list
}
b $ b
类型类型不匹配;发现:
List [(Any,Class [_>:Int with NullPointerException with Thread with
String])]必需:List [(AnyRef,Class [_])]
Type type mismatch; found : List[(Any, Class[_ >: Int with NullPointerException with Thread with String])] required: List[(AnyRef, Class[_])]
If dataSet4 is removed from List, the compile time error disappears
请注意,Class [_]有什么问题。是不是
相当于Java中的Class [?]我很感激,如果你还建议
正确的声明这样做..
Please suggest, what is wrong with Class[_]. Isn't it equivalent to Class[?] in java ? I appreciate, if you also suggest correct declaration for doing this..
推荐答案
在 Scala 中:
-
任何
类类的根。 / strong>,它延伸自 -
AnyVal
所有值类型的类别。它延伸自任何
-
Null
。 / strong>包括
Any
。 Null
Any
is the root of the Scala class.AnyRef
is the root of the class of reference types, it extends fromAny
.AnyVal
is the root class of all value types. it extends fromAny
Null
is a subtype of all reference types.Nothing
is a subtype of all other types includingNull
扩展任何
,包括 AnyRef:引用类型
和 AnyVal:values类型
。
def getValueAndItsType() : List[ (Any, _ <: Any) ] = {
val dataSet1 = ("some string data", classOf[String])
val dataSet2 = (new Thread(), classOf[Thread])
val dataSet3 = (new NullPointerException(), classOf[NullPointerException])
val list = List(dataSet1, dataSet2, dataSet3)
list
}
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