如何自动生成N“不同”颜色？ [英] How to automatically generate N "distinct" colors?

问题描述

我写了以下两种方法来自动选择N种不同的颜色。它通过在RGB立方体上定义分段线性函数来工作。这个的好处是你也可以得到一个渐进的尺度，如果这是你想要的，但是当N变大时，颜色可以开始看起来相似。我也可以想象均匀地将RGB立方体细分成一个点阵，然后绘制点。有没有人知道任何其他方法？我排除了定义列表，然后只是循环通过它。我还应该说，我一般不关心他们是否冲突或不好看，他们只是在视觉上不同。

I wrote the two methods below to automatically select N distinct colors. It works by defining a piecewise linear function on the RGB cube. The benefit of this is you can also get a progressive scale if that's what you want, but when N gets large the colors can start to look similar. I can also imagine evenly subdividing the RGB cube into a lattice and then drawing points. Does anyone know any other methods? I'm ruling out defining a list and then just cycling through it. I should also say I don't generally care if they clash or don't look nice, they just have to be visually distinct.

public static List<Color> pick(int num) {
    List<Color> colors = new ArrayList<Color>();
    if (num < 2)
        return colors;
    float dx = 1.0f / (float) (num - 1);
    for (int i = 0; i < num; i++) {
        colors.add(get(i * dx));
    }
    return colors;
}

public static Color get(float x) {
    float r = 0.0f;
    float g = 0.0f;
    float b = 1.0f;
    if (x >= 0.0f && x < 0.2f) {
        x = x / 0.2f;
        r = 0.0f;
        g = x;
        b = 1.0f;
    } else if (x >= 0.2f && x < 0.4f) {
        x = (x - 0.2f) / 0.2f;
        r = 0.0f;
        g = 1.0f;
        b = 1.0f - x;
    } else if (x >= 0.4f && x < 0.6f) {
        x = (x - 0.4f) / 0.2f;
        r = x;
        g = 1.0f;
        b = 0.0f;
    } else if (x >= 0.6f && x < 0.8f) {
        x = (x - 0.6f) / 0.2f;
        r = 1.0f;
        g = 1.0f - x;
        b = 0.0f;
    } else if (x >= 0.8f && x <= 1.0f) {
        x = (x - 0.8f) / 0.2f;
        r = 1.0f;
        g = 0.0f;
        b = x;
    }
    return new Color(r, g, b);
}

推荐答案

href =http://en.wikipedia.org/wiki/HSL_and_HSV =nofollow noreferrer> HSL颜色模型来创建颜色。

You can use the HSL color model to create your colors.

如果你想要的是不同的色调（可能），轻微或饱和度的轻微变化，你可以分配的色调如下：

If all you want is differing hues (likely), and slight variations on lightness or saturation, you can distribute the hues like so:

// assumes hue [0, 360), saturation [0, 100), lightness [0, 100)

for(i = 0; i < 360; i += 360 / num_colors) {
    HSLColor c;
    c.hue = i;
    c.saturation = 90 + randf() * 10;
    c.lightness = 50 + randf() * 10;

    addColor(c);
}

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