生成颜色渐变在C＃ [英] Generate Color Gradient in C#

问题描述

我的问题类似于这里的问题，但我使用的是C＃。 / p>

我有两种颜色，我有一个预定义步骤。如何检索 Color 的列表，它们是两者之间的渐变？

尝试，这不工作：

  int argbMax = Color.Chocolate.ToArgb 
 int argbMin = Color.Blue.ToArgb（）; 
 var colorList = new List< Color>（）; 
 
 for（int i = 0; i  {
 var colorAverage = argbMin +（int）（（argbMax- argbMin）* i / size）; 
 colorList.Add（Color.FromArgb（colorAverage））; 
} 
  

如果你尝试上面的代码，你会发现， code> argb 不对应于颜色的视觉渐进增加。

有任何想法吗？

解决方案

  int rMax = Color（R，G，B组件）对每个单独执行相同的线性插值，然后重新组合。 。 
 int rMin = Color.Blue.R; 
 // ...并且对于B，G 
 var colorList = new List< Color>（）; 
 for（int i = 0; i  {
 var rAverage = rMin +（int）（（rMax-rMin）* i / size）; 
 var gAverage = gMin +（int）（（gMax  -  gMin）* i / size）; 
 var bAverage = bMin +（int）（（bMax  -  bMin）* i / size）; 
 colorList.Add（Color.FromArgb（rAverage，gAverage，bAverage））; 
} 
  

My question here is similar to the question here, except that I am working with C#.

I have two colors, and I have a predefine steps. How to retrieve a list of Colors that are the gradients between the two?

This is an approach that I tried, which didn't work:

int argbMax = Color.Chocolate.ToArgb();
int argbMin = Color.Blue.ToArgb();
var colorList = new List<Color>();

for(int i=0; i<size; i++)
{
    var colorAverage= argbMin + (int)((argbMax - argbMin) *i/size);
    colorList.Add(Color.FromArgb(colorAverage));
}

If you try the above code, you will find that a gradual increase in argb doesn't correspond to a visual gradual increase in the color.

Any idea on this?

解决方案

You will have to extract the R, G, B components and perform the same linear interpolation on each of them individually, then recombine.

int rMax = Color.Chocolate.R;
int rMin = Color.Blue.R;
// ... and for B, G
var colorList = new List<Color>();
for(int i=0; i<size; i++)
{
    var rAverage = rMin + (int)((rMax - rMin) * i / size);
    var gAverage = gMin + (int)((gMax - gMin) * i / size);
    var bAverage = bMin + (int)((bMax - bMin) * i / size);
    colorList.Add(Color.FromArgb(rAverage, gAverage, bAverage));
}

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