颜色深浅响应div的数量 [英] Color shades responsive to number of divs

问题描述

我在一个工作板上工作，总是改变工作量。然而，每个职位发布应该有一个基本颜色的分层阴影：＃219BBE 。
这是我想要实现的草图：

I am working on a job board with an always changing quantity of job postings. However each job posting should have a tiered shade of one base color: #219BBE. Here is a sketch of what I am trying to achieve:

我需要的是一个javascript函数，它根据<$ c $的数量更改颜色的阴影c> job_box es。

What I need is a javascript function which changes the shade of a color depending on the number of job_boxes.

到目前为止，我发现了一个javascript代码片段，用于生成＃219BBE 。

So far I found a javascript snippet for generating the shades of #219BBE.

function calculateShades(colorValue) {
  "#219BBE" = colorValue;

// break the hexadecimal color value into R, G, B one-byte components
// and parse into decimal values.
// calculate a decrement value for R, G, and B based on 10% of their
// original values.
var red = parseInt(colorValue.substr(0, 2), 16);
var redDecrement = Math.round(red*0.1);

var green = parseInt(colorValue.substr(2, 2), 16);
var greenDecrement = Math.round(green*0.1);

var blue = parseInt(colorValue.substr(4, 2), 16);
var blueDecrement = Math.round(blue*0.1);

var shadeValues = [];
var redString = null;
var greenString = null;
var blueString = null;

for (var i = 0; i < 10; i++) {
  redString = red.toString(16); // convert red to hexadecimal string
  redString = pad(redString, 2); // pad the string if needed
  greenString = green.toString(16); // convert green to hexadecimal string
  greenString = pad(greenString, 2); // pad the string if needed
  blueString = blue.toString(16); // convert blue to hexadecimal string
  blueString = pad(blueString, 2); // pad the string if needed
  shadeValues[i] = redString + greenString + blueString;

// reduce the shade towards black
  red = red - redDecrement;
  if (red <= 0) {
    red = 0;
  }

  green = green - greenDecrement;
  if (green <= 0) {
    green = 0;
  }

  blue = blue - blueDecrement;
  if (blue <= 0) {
    blue = 0;
  }

}

shadeValues[10] = "000000";
return shadeValues;
}

我简化了这个问题的输出：
HTML

I simplified the output for this problem: HTML

<!-- Instead of 4 boxes we could also have n boxes -->
<div class="job_box"></div>
<div class="job_box"></div>
<div class="job_box"></div>
<div class="job_box"></div>

CSS

.job_box {
  width: 100%;
  height: 50px;

  /* The dynamic background-color */
  background-color: #219BBE;
}

要计算 job_box es我将使用jQuery：

To count the quantity of job_boxes I would use jQuery:

var numBoxes = $('.job_box').length

这里是我被困住的地方。我知道我需要一个循环，但这是它。请你向正确的方向推我吗？

And here is the point where I am stuck. I know that I need a loop but that's it. Can you please push me in the right direction?

Fiddle

推荐答案

这是我的解决方案： DEMO

var n = 0;

$('.job_box').each(function() {
    n++;
    lighten($(this), n);
});

function lighten(that, n) {
    var lightenPercent = 15 / n;
    var rgb = that.css('background-color');
    rgb = rgb.replace('rgb(', '').replace(')', '').split(',');
    var red = $.trim(rgb[0]);
    var green = $.trim(rgb[1]);
    var blue = $.trim(rgb[2]);

    red = parseInt(red * (100 - lightenPercent) / 100);
    green = parseInt(green * (100 - lightenPercent) / 100);
    blue = parseInt(blue * (100 - lightenPercent) / 100);

    rgb = 'rgb(' + red + ', ' + green + ', ' + blue + ')';

    that.css('background-color', rgb);
}

另一方面，您可以通过更改 / 到 * 。

You can, on the other hand, darken your base color by changing the / to * when setting the var for percent.

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