Java的ProcessBuilder在哪里执行命令？ [英] Where does Java's ProcessBuilder look to execute commands?

问题描述

当我使用 ProcessBuilder 执行命令时，它如何知道在哪里查找该命令？使用这个黑客/技巧我修改了我的PATH变量（通过检查 processBuilder.environment（）验证为坏（空，工作目录等），但ProcessBuilder仍然可以执行排序，echo，bash等等。

注意：我的特定开发环境是OSX，但是这个代码也可以在Red Hat Enterprise Linux上运行。

表示要调用的外部程序文件的字符串列表及其参数（如果有）。哪些字符串列表表示有效的操作系统命令是系统相关的。 [...]

这本质上意味着在哪里寻找程序执行取决于特定的系统和JVM运行。

我找不到一个完整的JVM / System行为矩阵，但是它的行为类似于系统的流行shell（ bash 代表* nix和 cmd 代表窗口），即它搜索 PATH 环境变量从左到右并执行它找到的第一个可执行文件。

When I execute a command using ProcessBuilder, how does it know where to look for that command? Using this hack/trick I've modified my PATH variable (verified by inspecting processBuilder.environment()) to be bad (empty, working dir, etc) but ProcessBuilder can still execute sort, echo, bash, etc. just fine. How is it doing this?!

Note: My particular development environment is OSX but this code will also run on Red Hat Enterprise Linux.

解决方案

The documentation says

[...] a command, a list of strings which signifies the external program file to be invoked and its arguments, if any. Which string lists represent a valid operating system command is system-dependent. [...]

Which in essence mean that where it looks for programs to execute depends on the particular system and JVM you're running on.

I can't find a complete matrix of JVM / System behaviors, but supposedly it behaves similar to the popular shells of the system (bash for *nix and cmd for windows) i.e. it searches the directories in the PATH environment variable from left to right and executes the first executable file it finds.

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