如何在Linux中执行单向diff？ [英] How do I do a one way diff in Linux?

问题描述

如何在Linux中执行单向diff？

How do I do a one way diff in Linux?

差异的正常行为：

通常，diff会告诉您两个文件之间的区别。例如，它会告诉你在文件A中不在文件B中的任何内容，并且还将告诉你在文件B中但不在文件A中的所有内容。例如：

Normally, diff will tell you all the differences between a two files. For example, it will tell you anything that is in file A that is not in file B, and will also tell you everything that is in file B, but not in file A. For example:

文件A包含：

cat
good dog
one
two

文件B包含 p>

File B contains:

cat
some garbage
one
a whole bunch of garbage
something I don't want to know

如果我做一个常规diff，如下：

If I do a regular diff as follows:

diff AB

diff A B

输出结果如下：

2c2
< good dog
---
> some garbage
4c4,5
< two
---
> a whole bunch of garbage
> something I don't want to know

我在找什么：

我想要的只是第一部分，例如，我想知道文件A中的所有内容，但不知道文件B.但是，我想忽略

What I want is just the first part, for example, I want to know everything that is in File A, but not file B. However, I want it to ignore everything that is in file B, but not in file A.

我想要的是命令或一系列命令：

???? AB

可产生输出：

2c2
< good dog
4c4,5
< two

我相信一个解决方案可以通过管道输出diff到sed或awk，我不太熟悉这些工具来提出一个解决方案。我基本上想要删除以---和>开头的所有行。

I believe a solution could be achieved by piping the output of diff into sed or awk, but I am not familiar enough with those tools to come up with a solution. I basically want to remove all lines that begin with --- and >.

编辑：我编辑了一个行上的多个单词的示例。

I edited the example to account for multiple words on a line.

注意：这是一个子问题：确定在RedHat Linux机器上安装的非操作系统软件包列表

Note: This is a "sub-question" of: Determine list of non-OS packages installed on a RedHat Linux machine

注意：类似，但不同于这里提出的问题（例如不是欺骗）：
单向差异文件

Note: This is similar to, but not the same as the question asked here (e.g. not a dupe): One-way diff file

推荐答案

diff AB | grep'^& awk'{print $ 2}'

grep'^<'以<

awk'{print $ 2}'表示选择第二列

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