Linux命令以树的形式打印目录结构 [英] Linux command to print directory structure in the form of a tree

问题描述

有没有任何linux命令，我可以调用从一个Bash脚本，将以树的形式打印目录结构，例如

  folder1 
 a.txt 
 b.txt 
 folder2 
 folder3 
  

解决方案

这是您寻找树，应该在大多数发行版中（也许作为可选的安装）？

 〜> tree -d / proc / self / 
 / proc / self / 
 |  -  attr 
 |  -  cwd  - > / proc 
 |  -  fd 
 | ` -  3  - > / proc / 15589 / fd 
 |  -  fdinfo 
 |  -  net 
 | |  -  dev_snmp6 
 | |  -  netfilter 
 | |  -  rpc 
 | | |  -  auth.rpcsec.context 
 | | |  -  auth.rpcsec.init 
 | | |  -  auth.unix.gid 
 | | |  -  auth.unix.ip 
 | | |  -  nfs4.idtoname 
 | | |  -  nfs4.nametoid 
 | | |  -  nfsd.export 
 | | ` -  nfsd.fh 
 | `-stat 
 |  -  root  - > / 
` -  task 
` -  15589 
 |  -  attr 
 |  -  cwd  - > / proc 
 |  -  fd 
 | ` -  3  - > / proc / 15589 / task / 15589 / fd 
 |  -  fdinfo 
` -  root  - > / 
 
 27个目录
  

取自维护者网页。 >

您可以添加选项 -L＃其中＃

删除 -d 以显示文件。

Is there any linux command that I can call from a Bash script that will print the directory structure in the form of a tree, e.g.,

folder1
   a.txt
   b.txt
folder2
   folder3

解决方案

is this what your looking for tree, should be in most distributions (maybe as an optional install)?

~> tree -d /proc/self/
/proc/self/
|-- attr
|-- cwd -> /proc
|-- fd
|   `-- 3 -> /proc/15589/fd
|-- fdinfo
|-- net
|   |-- dev_snmp6
|   |-- netfilter
|   |-- rpc
|   |   |-- auth.rpcsec.context
|   |   |-- auth.rpcsec.init
|   |   |-- auth.unix.gid
|   |   |-- auth.unix.ip
|   |   |-- nfs4.idtoname
|   |   |-- nfs4.nametoid
|   |   |-- nfsd.export
|   |   `-- nfsd.fh
|   `-- stat
|-- root -> /
`-- task
    `-- 15589
        |-- attr
        |-- cwd -> /proc
        |-- fd
        | `-- 3 -> /proc/15589/task/15589/fd
        |-- fdinfo
        `-- root -> /

27 directories

sample taken from maintainers web page.

You can add the option -L # where # is replaced by a number, to specify the max recursivity level.

Remove -d to display also files.

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