有没有办法忽略头文件行在UNIX排序? [英] Is there a way to ignore header lines in a UNIX sort?
问题描述
我有一个固定宽度字段文件,我试图使用UNIX(Cygwin,在我的情况下)排序实用程序排序。
问题是在文件顶部有一个两行标题,正在排序到文件的底部(因为每个标题行以冒号开头)。
有一种方法来告诉排序要么通过未排序的前两行,要么指定将冒号行排在顶部的排序 - 其余行总是以6位数字开始(这实际上是关键I'
示例:
: 0:12345
:1:6:2:3:8:4:2
010005TSTDOG_FOOD01
500123TSTMY_RADAR00
222334NOTALINEOUT01
477821USASHUTTLES21
325611LVEANOTHERS00
应排序为:
:0:12345
:1:6:2:3:8:4:2
010005TSTDOG_FOOD01
222334NOTALINEOUT01
325611LVEANOTHERS00
477821USASHUTTLES21
500123TSTMY_RADAR00
-n 2< file> &&& tail -n +3< file> |排序)>新文件
括号创建一个子shell,包装stdout,以便管道或重定向它来自一个命令。
I have a fixed-width-field file which I'm trying to sort using the UNIX (Cygwin, in my case) sort utility.
The problem is there is a two-line header at the top of the file which is being sorted to the bottom of the file (as each header line begins with a colon).
Is there a way to tell sort either "pass the first two lines across unsorted" or to specify an ordering which sorts the colon lines to the top - the remaining lines are always start with a 6-digit numeric (which is actually the key I'm sorting on) if that helps.
Example:
:0:12345
:1:6:2:3:8:4:2
010005TSTDOG_FOOD01
500123TSTMY_RADAR00
222334NOTALINEOUT01
477821USASHUTTLES21
325611LVEANOTHERS00
should sort to:
:0:12345
:1:6:2:3:8:4:2
010005TSTDOG_FOOD01
222334NOTALINEOUT01
325611LVEANOTHERS00
477821USASHUTTLES21
500123TSTMY_RADAR00
(head -n 2 <file> && tail -n +3 <file> | sort) > newfile
The parentheses create a subshell, wrapping up the stdout so you can pipe it or redirect it as if it had come from a single command.
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