如何使用python的BaseHTTPServer / SimpleHTTPServer调试POST请求？ [英] How can I debug POST requests with python's BaseHTTPServer / SimpleHTTPServer?
问题描述
我在此网站上找到一个脚本，用于通过命令行使用python运行简单的服务器。
I found a script on this site for running a simple server via the command line with python.
我添加了一些打印行，因为我想通过命令行打印出GET和POST参数的请求，
I added some print lines in because I'd like to print out the GET and POST parameters via the command line for requests, but I can't seem to get them to show up anywhere.
如果我只是打印我们的 s 变量（ pprint（vars（s）））我最终看到这个：
If I just print our our the s variable (pprint (vars(s))) I end up seeing this:
{'client_address': ('127.0.0.1', 53373),
'close_connection': 1,
'command': 'GET',
'connection': <socket._socketobject object at 0x10b6560c0>,
'headers': <mimetools.Message instance at 0x10b689ab8>,
'path': '/favicon.ico',
'raw_requestline': 'GET /favicon.ico HTTP/1.1\r\n',
'request': <socket._socketobject object at 0x10b6560c0>,
'request_version': 'HTTP/1.1',
'requestline': 'GET /favicon.ico HTTP/1.1',
'rfile': <socket._fileobject object at 0x10b6538d0>,
'server': <BaseHTTPServer.HTTPServer instance at 0x10b6893f8>,
'wfile': <socket._fileobject object at 0x10b6536d0>}
我试图使用 print 命令和每个索引（ pprint（vars（s.connection）） ）
I tried to then use the print command with each of the indices, (pprint (vars(s.connection))) but that's not working.
这是修改后的脚本：
#!/usr/bin/python
import time
import BaseHTTPServer
from pprint import pprint
HOST_NAME = 'localhost' # !!!REMEMBER TO CHANGE THIS!!!
PORT_NUMBER = 9000 # Maybe set this to 9000.
class MyHandler(BaseHTTPServer.BaseHTTPRequestHandler):
def do_HEAD(s):
s.send_response(200)
s.send_header("Content-type", "text/html")
s.end_headers()
def do_GET(s):
"""Respond to a GET request."""
s.send_response(200)
s.send_header("Content-type", "text/html")
s.end_headers()
s.wfile.write("<html><head><title>Title goes here.</title></head>")
s.wfile.write("<body><form action='.' method='POST'><input name='x' value='1' /><input type='submit' /></form><p>This is a test.</p>")
# If someone went to "http://something.somewhere.net/foo/bar/",
# then s.path equals "/foo/bar/".
s.wfile.write("<p>GET: You accessed path: %s</p>" % s.path)
s.wfile.write("</body></html>")
pprint (vars(s))
def do_POST(s):
"""Respond to a POST request."""
s.send_response(200)
s.send_header("Content-type", "text/html")
s.end_headers()
s.wfile.write("<html><head><title>Title goes here.</title></head>")
s.wfile.write("<body><p>This is a test.</p>")
s.wfile.write("<body><form action='.' method='POST'><input type='text' name='xxxxxxxxxxxx' value='0000000000000000000000' /><input type='submit' /></form><p>This is a test.</p>")
# If someone went to "http://something.somewhere.net/foo/bar/",
# then s.path equals "/foo/bar/".
s.wfile.write("<p>POST: You accessed path: %s</p>" % s.path)
s.wfile.write("</body></html>")
pprint (vars(s))
pprint (vars(s.connection))
pprint (vars(s.headers))
pprint (vars(s.request))
pprint (vars(s.rfile))
pprint (vars(s.server))
pprint (vars(s.wfile))
pprint (vars(s.fp))
"""pprint (vars(s.request))"""
if __name__ == '__main__':
server_class = BaseHTTPServer.HTTPServer
httpd = server_class((HOST_NAME, PORT_NUMBER), MyHandler)
print time.asctime(), "Server Starts - %s:%s" % (HOST_NAME, PORT_NUMBER)
try:
httpd.serve_forever()
except KeyboardInterrupt:
pass
httpd.server_close()
print time.asctime(), "Server Stops - %s:%s" % (HOST_NAME, PORT_NUMBER)
如何使用简单脚本打印POST和GET参数？
How can I print out POST and GET parameters using a simple script?
通过命令行输出的命令如下：
Desired output via the command line would look something like:
1.0.0.127. - - [03/Oct/2012 16:02:05] "POST / HTTP/1.1" 200 -
foo=1
bar=2
bis=3
推荐答案
这不是非常明显，但是处理程序在后台使用套接字。因此，您需要从套接字读取原始数据，然后解释它。
It's not tremendously obvious, but the handler is using sockets behind the scenes. So you need to read the raw data from the socket, and then interpret it.
使用 urlparse 模组。
- 2，你需要
urlparse.parse_qs。 - 在Python 3中，库被重命名：
urllib .parse.parse_qs。
- In Python 2, you want
urlparse.parse_qs. - In Python 3, the library is renamed: you want
urllib.parse.parse_qs.
导入 urlparse ，然后修改 do_POST 方法，如下所示：
Import urlparse, and then modify your do_POST method like so:
def do_POST(s):
"""Respond to a POST request."""
# Extract and print the contents of the POST
length = int(s.headers['Content-Length'])
post_data = urlparse.parse_qs(s.rfile.read(length).decode('utf-8'))
for key, value in post_data.iteritems():
print "%s=%s" % (key, value)
s.send_response(200)
s.send_header("Content-type", "text/html")
s.end_headers()
...
设置一个简单的测试客户端：
Set up a simple test client:
#!/usr/bin/env python
import urllib
import urllib2
url = 'http://localhost:9000'
post_dict = {'foo' : 1,
'bar' : 2,
'bis' : 3}
params = urllib.urlencode(post_dict)
post_req = urllib2.Request(url)
post_req.add_data(params)
response = urllib2.urlopen(post_req)
response_data = response.read()
response.close()
print response_data
启动服务器，然后运行客户端：
Start the server, and then run the client:
ire@localhost$ python http_server.py
Wed Oct 3 21:38:51 2012 Server Starts - localhost:9000
foo=[u'1']
bar=[u'2']
bis=[u'3']
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