如何从ARGV获取长文件名 [英] How to get long filename from ARGV
问题描述
我想创建一个需要一些文件名作为参数的工具,但是当我使用此代码时:
I want to make a tool that takes some filenames as parameters, but when I use this code:
ARGV.each do|a|
puts "Argument: #{a}"
end
拖放或发送到在Windows中,我得到短文件名。
因此,像C:\Ruby193\bin\test\New Text Document.txt
的文件变为
C:\Ruby193\bin\test\NEWTEX〜1.TXT
作为参数。
and I use drag and drop or "send to" in Windows, I get the short filename.
So a file like "C:\Ruby193\bin\test\New Text Document.txt"
becomes
C:\Ruby193\bin\test\NEWTEX~1.TXT
as the argument.
没有问题
当我使用拖放或发送时,如何获取长文件名?
How do i get the long filename when i use drag and drop or send to?
推荐答案
我不知道是否可以改变拖放的参数,但你可以使用Win32 < a href =http://msdn.microsoft.com/en-us/library/windows/desktop/aa364980%28v=vs.85%29.aspx =nofollow> getLongPathName( )
功能,使用 Ruby Win32绑定
I don't know if it is possible to change the argument you recieve on a drag and drop, but you could use the Win32 getLongPathName()
function, using the Ruby Win32 bindings
- edit--
包括@ peter的解决方案格式化为可读性:
--edit--
Including @peter's solution formatted for readability:
require 'find'
require 'fileutils'
require 'Win32API'
def get_long_win32_filename(short_name)
max_path = 1024
long_name = " " * max_path
lfn_size = Win32API.new("kernel32",
"GetLongPathName", ['P','P','L'],'L').call(short_name, long_name, max_path)
return (1..max_path).include?(lfn_size) ? long_name[0..lfn_size-1] : short_name
end
ARGV.each do|a|
puts a
puts get_long_win32_filename(a)
end
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