向batch / powershell添加超时 [英] adding a timeout to batch/powershell

问题描述

$fullnamexp = ((net user $winxp /domain | Select-String "Full Name") -replace "Full Name","").Trim();

如果找不到 $ winxp 命令将挂起，有一个超时，我可以使用这个使它在5-10秒后移动？不确定我会把它放在哪里。

If $winxp cannot be found, the command will hang, is there a timeout I can use with this to make it move on after 5-10 seconds? Not sure where I would put it.

编辑 - 我使用这个来拉用户名：

Edit- I use this to pull the username:

$reg  = [Microsoft.Win32.RegistryKey]::OpenRemoteBaseKey('LocalMachine', $tag1)
$key  = $reg.OpenSubKey('SOFTWARE\Microsoft\Windows NT\CurrentVersion\WinLogon')
$winxp = $key.GetValue('DefaultUserName') -replace '^.*?\\'

$ winxp 是一个登录名，例如 ajstepanik 那么我把它放入： $ fullnamexp =（（net user $ winxp / domain | Select-StringFull Name）-replaceFull Name，）Trim c $ c>

$winxp is then a login name such as ajstepanik then I put it into: $fullnamexp = ((net user $winxp /domain | Select-String "Full Name") -replace "Full Name","").Trim();

1.21.2014更新

 $timeoutSeconds = 5
$code = {
    ((net user $winxp /domain | Select-String "Full Name") -replace "Full Name","").Trim(); # your commands here, e.g.
}
$j = Start-Job -ScriptBlock $code
if (Wait-Job $j -Timeout $timeoutSeconds) { $fullnamexp = Receive-Job $j }
Remove-Job -force $j

推荐答案

@mjolinor确实为您提供了一种替代方法，这里直接回答您的一般问题：如何在PowerShell中强制超时？

While @mjolinor may have indeed provided you an alternative approach, here is a direct answer to your general question: how do you force a timeout in PowerShell?

您希望在脚本块中设置时间限制，将其作为作业运行，然后使用 Wait-Job cmdlet对操作进行时间限制。 > 。在 Wait-Job 返回后，可以检查作业状态（ $ j.state ）以确定是否中断

Wrap whatever you wish to time-limit in a script block, run that as a job, then use the Wait-Job cmdlet to time-limit the operation. Wait-Job will return either at the end of the timeout period or when the script block completes, whichever occurs first. After Wait-Job returns, you can examine the job state ($j.state) to determine whether it was interrupted or not, if it matters to you.

$timeoutSeconds = 5 # set your timeout value here
$j = Start-Job -ScriptBlock {
    # your commands here, e.g.
    Get-Process
    }
"job id = " + $j.id # report the job id as a diagnostic only
Wait-Job $j -Timeout $timeoutSeconds | out-null
if ($j.State -eq "Completed") { "done!" }
elseif ($j.State -eq "Running") { "interrupted" }
else { "???" }
Remove-Job -force $j #cleanup

这里有一个简化的方法，它还包括使用 Receive-Job ，假设您希望在stdout上生成：

Here is a bit more streamlining approach that also includes the practical step of getting information out of the script block with Receive-Job, assuming what you want is generated on stdout:

$timeoutSeconds = 3
$code = {
    # your commands here, e.g.
    Get-ChildItem *.cs | select name
}
$j = Start-Job -ScriptBlock $code
if (Wait-Job $j -Timeout $timeoutSeconds) { Receive-Job $j }
Remove-Job -force $j

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