如何删除仅以“//”开头的JavaScript评论？ [英] How do I remove ONLY JavaScript comments that start with "// "?

问题描述

首先，我已经有一个压缩工具，成功压缩其他所有，所以我不需要一个长的复杂 preg_replace regex，只是一个简单的 preg_replace 或 str_replace 规则。

To clarify first, I already have a compression tool that successfully compresses EVERYTHING else so I don't need a long complicated preg_replace regex, just a simple preg_replace or str_replace rule will do.

我只想删除JavaScript以//开头的评论（包括空格，所以我不删除URL）直到新行。而已！再次，我不需要替换/ * * /或任何其他变体，因为我有一个脚本，这已经;它缺少的唯一的东西是这一个功能，所以我想清理输入与这第一，然后交给脚本。

I ONLY want to remove JavaScript comments that start with "// " (including the space so I don't erase URLs) up until the new line. THAT'S IT! Once again, I don't need to replace /* */ or any other variations as I have a script that does that already; the only thing it's missing is this one feature so I want to clean up the input with this first, then hand it over to the script.

这里是截图与示例我要删除的评论：

Here are screenshots with examples of comments I would like to remove:

我真的很感激这个帮助！ :-) THANKS！

I would really appreciate help with this! :-) THANKS!

推荐答案

尝试以下代码：

$re = "~\\n? */{2,} .*~"; 
$str = "text\n\n/*\ntext\n*\n    //example1\n    //example2\n\ntext\n\n//   example 3"; 
$subst = ""; 

$result = preg_replace($re, $subst, $str);

正则表达式匹配两个或多个 / 通过像你在问题中提出的空间。更换时将删除整行或直到

The regex matches two or more / following by a space like you asked in the question. When you replace it will erase the whole line or until the spaces and line breaks that were

演示

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