数值比较难度 [英] Numeric comparison difficulty in R
问题描述
我试图比较R中的两个数字作为if语句条件的一部分:
I'm trying to compare two numbers in R as a part of a if-statement condition:
(ab)> = 0.5
在这个特定实例中,a = 0.58和b = 0.08 ...还有 ; = 0.5
为false。我知道使用 ==
进行确切的数字比较的危险,这似乎相关:
In this particular instance, a = 0.58 and b = 0.08... and yet (a-b) >= 0.5
is false. I'm aware of the dangers of using ==
for exact number comparisons, and this seems related:
code>(a - b)== 0.5)为false,而
(a - b) == 0.5)
is false, while
all.equal (a-b),0.5)
是真的。
我可以想到的唯一解决方案是有两个条件:(ab)> 0.5 | all.equal((a-b),0.5)
。这工作,但是这真的是唯一的解决方案吗?我应该只是发出 =
家族的比较运算符吗?
The only solution I can think of is to have two conditions: (a-b) > 0.5 | all.equal((a-b), 0.5)
. This works, but is that really the only solution? Should I just swear off of the =
family of comparison operators forever?
/ strong>我知道这是一个浮点问题。更基本的是,我要问的是:我该怎么办?因为> =
不能真正被信任,所以在R中处理大于或等于比较是一个明智的方法吗?
Edit for clarity: I know that this is a floating point problem. More fundamentally, what I'm asking is: what should I do about it? What's a sensible way to deal with greater-than-or-equal-to comparisons in R, since the >=
can't really be trusted?
推荐答案
我从来不是这样的事情的 all.equal
的粉丝。在我看来,容忍有时以神秘的方式工作。为什么不检查大于0.05以下的公差
I've never been a fan of all.equal
for such things. It seems to me the tolerance works in mysterious ways sometimes. Why not just check for something greater than a tolerance less than 0.05
tol = 1e-5
(a-b) >= (0.05-tol)
一般来说,我发现直逻辑比all.equal更好。
In general, without rounding and with just conventional logic I find straight logic better than all.equal
如果 x == y
那么 xy == 0
。也许 xy
不完全是0,所以对于这种情况,我使用
If x == y
then x-y == 0
. Perhaps x-y
is not exactly 0 so for such cases I use
abs(x-y) <= tol
您必须为 all .equal
,这比 all.equal
更紧凑和直接。
You have to set tolerance anyway for all.equal
and this is more compact and straightforward than all.equal
.
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