如何在Java中比较两个Hash Map [英] How to compare two Hash Maps in Java

问题描述

  HashMap1：$ HashMap b $ b键：BOF值：SAPF 
键：BOM值：SAPM 
键：BOL值：SAPL 
 
 HashMap2：
键：BOF值：Data1 
键：BOL值：Data2 
  

在比较这两个哈希以后，我的结果hashmap将包含键作为第一个HashMap1的值和值作为第二个HashMap2的值。

  HashMap3：
键：SAPF值：Data1 
键：SAPL值：Data2 
  

解决方案

只需迭代 HashMap1 的键，对于每个键，检查它是否存在于 HashMap2 中。
如果存在，请将值添加到 HashMap3 ：

  final Map< String，String> hm1 = new HashMap< String，String>（）; 
 hm1.put（BOF，SAPF）; 
 hm1.put（BOM，SAPM）; 
 hm1.put（BOL，SAPL）; 
 
 final Map< String，String> hm2 = new HashMap< String，String>（）; 
 hm2.put（BOF，Data1）; 
 hm2.put（BOL，Data2）; 
 
 final Map< String，String> hm3 = new HashMap< String，String>（）; 
 
 for（final String key：hm1.keySet（））{
 if（hm2.containsKey（key））{
 hm3.put（hm1.get（key） hm2.get（key））; 
} 
} 
  

Hi I am working with HashMap in java and i have a scenario where i have to compare 2 HashMaps

HashMap1:
Key: BOF   Value: SAPF
Key: BOM   Value: SAPM
Key: BOL   Value: SAPL

HashMap2:
Key: BOF   Value: Data1
Key: BOL   Value: Data2

And after comparing these two hashmaps my resulting hashmap will contain the Key as a Value of First HashMap1 and Value as a Value of second HashMap2.

HashMap3:
Key: SAPF  Value: Data1
Key: SAPL  Value: Data2

解决方案

Just iterate on the keys of HashMap1, and for each key, check if it's present in HashMap2. If it's present, add the values to HashMap3 :

final Map<String, String> hm1 = new HashMap<String, String>();
hm1.put("BOF", "SAPF");
hm1.put("BOM", "SAPM");
hm1.put("BOL", "SAPL");

final Map<String, String> hm2 = new HashMap<String, String>();
hm2.put("BOF", "Data1");
hm2.put("BOL", "Data2");

final Map<String, String> hm3 = new HashMap<String, String>();

for (final String key : hm1.keySet()) {
    if (hm2.containsKey(key)) {
        hm3.put(hm1.get(key), hm2.get(key));
    }
}

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