对Object.clone()的功能引用不会编译 [英] Functional reference to Object.clone() doesn't compile
问题描述
import java .util.concurrent.Callable;
class Ideone
{
Callable<?> x = super :: clone;
}
使用Oracle JDK提供:
Main.java:6:错误:不兼容类型:无效方法引用
可调用<?> x = super :: clone;
^
clone()在Object
中具有受保护的访问权限因为类应该能够访问其父的受保护方法。这个表达式在Eclipse的编译器中工作良好。
此外,()这是一个错误吗?
super
实际上不是一个表达式,没有静态类型。 super.foo()
具有与 this.foo()
相同的访问权限;这就是说,方法调用在字节代码中以不同的方式翻译为超级调用,而不是正常调用。
JLS在此不是很清楚;例如在受保护的访问部分中, a>,未提及 super.protectedMember
表单;但显然这种形式应该在JLS中讨论;它应该是可访问的。 (该部分确实建议 X :: m
和 Xm
应该被视为相同的wrt访问权限)
在方法参考,措辞也是模糊的;但是, super :: clone
应该可以访问 super.clone()
>
已创建一个错误报告: JDK- 8139836:当x受保护时不能使用super :: x方法引用。它的当前状态是它将在Java 9中修复。
import java.util.concurrent.Callable;
class Ideone
{
Callable<?> x = super::clone;
}
using Oracle JDK gives:
Main.java:6: error: incompatible types: invalid method reference
Callable<?> x = super::clone;
^
clone() has protected access in Object
which makes no sense as a class should be able to access its parent's protected methods. This expression works fine in Eclipse's compiler.
Also, () -> super.clone()
compiles fine....
Is this a bug?
super
is not actually an expression, and there's no static type to talk about. super.foo()
has the same access as this.foo()
; it's just that, the method invocation is translated differently in byte code, as "super invoke", as opposed to "normal invoke".
JLS is not very clear on this; e.g. in section of protected access, the super.protectedMember
form is not mentioned; but obviously that form should be discussed in JLS; and it should be accessible. (The section does suggest that X::m
and X.m
should be treated the same w.r.t. access right)
In the section of method reference, the wording is also vague; nevertheless, super::clone
should be accessible the same ways as super.clone()
is accessible.
A bug report has been created: JDK-8139836: "Can't use super::x method reference when x is protected". Its current status is that it will be fixed in Java 9.
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