模式匹配Erlang？ [英] Pattern Matching Erlang?

问题描述

我有一个if语句的代码，试图让用户输入yes或no，如果用户输入的东西不是yes的请求被拒绝。这是我得到的错误：

I have this code with a if statement which is trying to get the user to input yes or no if the user inputs anything other than yes the request is denied. This is the error I get:

** exception error: no match of right hand side value "yes\n"
     in function  messenger:requestChat/1 (messenger.erl, line 80)

requestChat(ToName) ->
    case whereis(mess_client) of
        undefined ->
            not_logged_on;
         _ -> mess_client ! {request_to, ToName},
                request_to = io:get_line("Do you want to chat?"),
                {_, Input} = request_to,
                if(Input == yes) ->
                    ok;
                    true -> {error, does_not_want_to_chat}
                end
    end.

推荐答案

在这种情况下，

如果您尝试：

1> io:get_line("test ").
test yes
"yes\n"
2>

您可以看到io：get_line / 1不返回元组 { ok，Input} 但是一个简单的字符串由aa回车符结束：yes\\\
。

you can see that io:get_line/1 does not return a tuple {ok,Input} but a simple string terminated by a a carriage return: "yes\n". That is what it is reported in the error message.

因此，您的代码可以修改为：

So your code can be modified to:

requestChat(ToName) ->
    case whereis(mess_client) of
        undefined ->
            not_logged_on;
         _ -> mess_client ! {request_to, ToName},
                if 
                    io:get_line("Do you want to chat?") == "yes\n" -> ok;
                    true -> {error, does_not_want_to_chat}
                end
    end.

但我更喜欢案例语句

    requestChat(ToName) ->
        case whereis(mess_client) of
            undefined ->
                not_logged_on;
             _ -> mess_client ! {request_to, ToName},
                    case io:get_line("Do you want to chat?") of
                        "yes\n" -> ok;
                        "Yes\n" -> ok;
                        _ -> {error, does_not_want_to_chat}
                    end
        end.

这篇关于模式匹配Erlang？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！