console.log对象处于当前状态 [英] console.log object at current state

问题描述

console.log 将显示处于最后执行状态的对象，而不是显示 console.log 被调用。

我必须克隆对象，只是通过 console.log

如何更改console.log的默认行为？ （

）

  var test = {a：true} 
 console.log（test）; // {a：false} 
 test.a = false; 
 console.log（test）; // {a：false} 
  

解决方案

找到 console.dir（）。

console.log code>不会做你想要的，因为它打印一个对象的引用，当你弹出它打开，它的改变。 console.dir 在调用对象时打印对象中属性的目录。

JSON构思下面是一个好的;你甚至可以继续解析JSON字符串，并得到一个可浏览的对象，如.dir（）会给你：

console.log JSON.parse（JSON.stringify（obj）））;

console.log will show the object at the last state of execution, not at the state when console.log was called.

I have to clone the object just to output it via console.log to get the state of the object at that line.

How can I change the default behavior of console.log? (Error console in safari, no add-on)

Example:

var test = {a: true}
console.log(test); // {a: false}
test.a = false; 
console.log(test); // {a: false}

解决方案

I think you're looking for console.dir().

console.log() doesn't do what you want because it prints a reference to the object, and by the time you pop it open, it's changed. console.dir prints a directory of the properties in the object at the time you call it.

The JSON idea below is a good one; you could even go on to parse the JSON string and get a browsable object like what .dir() would give you:

console.log(JSON.parse(JSON.stringify(obj)));

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