可能启用“严格模式”;在FireBug和Chrome的控制台？ [英] Possible to enable "strict mode"; in FireBug and Chrome's console?
问题描述
使用此页面：
<!DOCTYPE html>
<html>
<head>
<script>
"use strict";
var foo = 2;
delete foo;
</script>
</head>
<body></body>
</html>
Firebug控制台提供：
Firebug console gives:
applying the 'delete' operator to an unqualified name is deprecated
>>> foo
ReferenceError: foo is not defined
foo
：
>>> var bar = 2;
undefined
>>> delete bar;
true
即使您注释掉 delete foo; code>，以便脚本不会中断，删除 bar 仍然成功，尽管事实它是一个全局对象的属性，因为它是通过变量声明创建的 DontDelete属性：
Even if you comment out delete foo; so that the script does not break, deleting bar is still successful despite the fact it "is a property of a Global object as it is created via variable declaration and so has DontDelete attribute":
>>> foo
2
>>> delete foo
false
>>> var bar = 2;
undefined
>>> delete bar
true
可以启用strict mode在FireBug和Chrome的控制台中？
Is it possible to enable "strict mode"; in FireBug and or Chrome's console?
推荐答案
firebug控制台通过在eval调用中包装所有代码，语句在你的脚本中不再是使用严格 - 因此它被禁用。你可以尝试在一个函数中包装你的代码，以强制执行使用严格的特定功能，但我知道的最好的解决方案是跳过控制台，并直接在页面本身测试。
The firebug console works by wrapping all the code in an "eval" call so the first statement in your script is no longer "use strict" - hence it is disabled. You could try wrapping your code in a function to enforce "use strict" for that particular function but the best solution I know of is to skip the console and test straight in the page itself.
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