强制通用接口实现在C＃ [英] Force generic interface implementation in C#

问题描述

有没有反对强制一个通用定义的约束实现一个通用接口...也就是说，我想类支持传递一个接口和一个类约束它，使类实现接口。例如，如果我说：

Is there anyway to force a constraints for a generic definition to implement a "generic interface" ... that is, I want the class to support passing an interface and a generic class constraining it so that the class implements the interface. For example if I say:

MyGenericClass<IMyInterface, MyImplementation>.DoSomething();

这应该限制使MyImplementation实现IMyInterface

That should be constrained so that MyImplementation implements IMyInterface

据我所知，可以通过

public class Dynamic_Loader<T, S> where S: T

现在，有没有还强制T是一个接口？

Now, is there anyway to also force T to be an interface?

修改：这样做的目的是：

private static List<T> interfaceList = new List<T>();

public static List<T> InterfaceList {get { return interfaceList;}}

public static void Add(S input) { interfaceList.Add(input);}

并且列表仅限于接口（因为它应该返回某些接口的实现）

and have the list restricted to only interfaces (since it is supposed to return implementations of certain interfaces)

推荐答案

你也可以在 T c $ c>？

Do you mean, can a constraint also be put on T like where T : interface?

如果是这样，则否：这份清单几乎涵盖您的选项。

If so, then no: this list pretty much covers your options.

我相信。

出于好奇，你想要约束 T 是一个接口？

Out of curiosity, what would be your reason for wanting to constrain T to be an interface?

或者你的意思是可以在 T T 到实现某些特定界面？

Or do you mean can a constraint also be put on T for T to implement some specific interface?

如果是这样，则是：只需要两个其中子句（例如，其中S：T其中T： U ）。

If so, then yes: simply have two where clauses (e.g., where S : T where T : U).

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