Rails：显示记录数的时间顺序 [英] Rails: Display chronological order of number of records

问题描述

在rails中显示表记录列表时，我有一个列，显示每个记录的id（以便查看表中有多少条记录）
唯一的问题是，例如，如果record数字3被删除，然后id也被删除（由于唯一性）。

而不是显示id，是有一种方法，我可以列出1,2,3 ，4,5等当查看列表？
在表中？

这是我的表：

 < center> 
< p class =recordnumber><％= pluralize（@ ranches.size，'Ranch'）％>发现< p> 
 
<％= render：partial => shared / newlink％> 
 
< table class =listingsummary =Ranches> 
< tr> 
< th>＃< / th> 
< th>牧场名称< / th> 
< th>地址< / th> 
< th>电话< / th> 
< th>操作< / th> 
< / tr> 
<％@ ranches.each do | ranch | ％> 
< tr class =<％= cycle（'odd'，'even'）％>> 
< td><％= ranch.id％>< / td> 
< td><％= ranch.name％>< / td> 
< td><％= ranch.address_line_1％>，< / br><％= ranch.town_city％>，< / br><％= ranch.postcode％> < / td> 
< td><％= ranch.telephone％>< / td> 
< td> 
<％= link_to（Edit，{：action =>'edit'，：id => ranch.id}，：class =>'buttons'）％> 
<％= link_to（Delete，{：action =>'delete'，：id => ranch.id}，：class =>'buttons'）％> 
< / td> 
< / tr> 
<％end％> 
< / table> 
  

解决方案>

是的。将替换为 each_with_index ，如下所示：

 <％@ ranches.each_with_index do | ranch，i | ％> 
< tr class =<％= cycle（'odd'，'even'）％>> 
< td><％= i + 1％>< / td> 
< td><％= ranch.name％>< / td> 
 .... 
  

i + 1 是因为 each_with_index 从零开始。

In rails when displaying a list of table records, I have a column which displays the id of each record (so as to see how many records exist in the table) The only problem is for example is if record number 3 is deleted, then the id is also removed (due to uniqueness).

Instead of displaying the id, is there a way I can list 1,2,3,4,5 etc when viewing the list? in a table?

This is my table :

  <center>
  <p class="recordnumber"><%= pluralize(@ranches.size, 'Ranch') %> found<p>

  <%= render :partial => "shared/newlink" %>

  <table class="listing" summary="Ranches">
   <tr>
    <th>#</th>
    <th>Ranch Name</th>
    <th>Address</th>
    <th>Telephone</th>
    <th>Actions</th>
   </tr>
   <% @ranches.each do |ranch| %>
   <tr class="<%= cycle('odd', 'even') %>">
    <td><%= ranch.id %></td>
    <td><%= ranch.name %></td>
    <td><%= ranch.address_line_1 %>,</br><%= ranch.town_city %>,</br><%= ranch.postcode %></td>
    <td><%= ranch.telephone %></td>
    <td>
     <%= link_to("Edit", {:action => 'edit', :id => ranch.id}, :class => 'buttons') %>
     <%= link_to("Delete", {:action => 'delete', :id => ranch.id}, :class => 'buttons') %>
    </td>
    </tr>
   <% end %>
  </table>

解决方案

Yes. Replace each with each_with_index like this:

<% @ranches.each_with_index do |ranch, i| %>
   <tr class="<%= cycle('odd', 'even') %>">
    <td><%= i + 1 %></td>
    <td><%= ranch.name %></td>
....

The i + 1 is there because each_with_index starts at zero.

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