Preg匹配和计算结果匹配在一个短字符串 [英] Preg matching and counting the resulting match in a short string

问题描述

我已经有一个函数计算字符串中的项目数（$段），并告诉我结果是多少字符，即tsp和tbsp目前是7，我可以使用这个来计算出的百分比字符串是

我需要通过preg_match强化这一点，因为10tsp应该计为5。

  $ characters = strlen（$ paragraph）; 
 $ items = array（tsp，tbsp，tbs）; 
 $ count = 0; 
 
 foreach（$ items as $ item）{
 
 //计算段落中的格式化次数
 $ countitems = substr_count（$ paragraph， $ item）; 
 $ countlength =（strlen（$ item）* $ countitems）; 
 
 $ count = $ count + $ countlength; 
} 
 
 $ overallpercent =（（100 / $ characters）* $ count）; 
  

我知道它会像 preg_match（'＃[d] [item]＃'，$ paragraph）对不对？

EDIT

解决方案

这不清楚我是什么正试图用正则表达式，但如果你只是想匹配一个特定的数字测量组合，这可能有助于：

  $ count = preg_match_all（'/ \d + \s *（tbsp | tsp | tbs）/'，$ paragraph）; 
  

这将返回 $中出现数字测量组合的次数

计算匹配字符数的示例：

  $ paragraph =5tbsp and 10 tsp; 
 
 $ charcnt = 0; 
 $ matches = array（）; 
 if（preg_match_all（'/ \d + \s *（tbsp | tsp | tbs）/'，$ paragraph，$ matches）> 0）{
 foreach（$ matches [0] as $ match）{$ charcnt + = strlen（$ match）; } 
} 
 
 printf（total number of characters：％d\\\
，$ charcnt）; 
  

执行上述输出：

总字符数：11

I already have a function that counts the number of items in a string ($paragraph) and tells me how many characters the result is, ie tsp and tbsp present is 7, I can use this to work out the percentage of that string is.

I need to reinforce this with preg_match because 10tsp should count as 5.

$characters = strlen($paragraph);
$items = array("tsp", "tbsp", "tbs");
    $count = 0;

        foreach($items as $item) {

            //Count the number of times the formatting is in the paragraph
            $countitems = substr_count($paragraph, $item);
            $countlength= (strlen($item)*$countitems);

            $count = $count+$countlength;
        }

    $overallpercent = ((100/$characters)*$count);

I know it would be something like preg_match('#[d]+[item]#', $paragraph) right?

EDIT sorry for the curve ball but there might be a space inbetween the number and the $item, can one preg_match catch both instances?

解决方案

It's not quite clear to me what you are trying to do with the regex, but if you are just trying to match for a particular number-measurement combination, this might help:

$count = preg_match_all('/\d+\s*(tbsp|tsp|tbs)/', $paragraph);

This will return the number of times a number-measurement combination occurs in $paragraph.

EDIT switched to use preg_match_all to count all occurrences.

Example for counting the number of matched characters:

$paragraph = "5tbsp and 10 tsp";

$charcnt = 0;
$matches = array();
if (preg_match_all('/\d+\s*(tbsp|tsp|tbs)/', $paragraph, $matches) > 0) {
  foreach ($matches[0] as $match) { $charcnt += strlen($match); }
}

printf("total number of characters: %d\n", $charcnt);

Output from executing the above:

total number of characters: 11

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