如何以编程方式创建新的cron作业？ [英] How can I programmatically create a new cron job?

问题描述

我想要能够以编程方式添加新的cron作业，最好的方法是什么？

从我的研究，似乎我可以转储当前的crontab，然后附加一个新的，管道系统回到crontab：

 （crontab -l; echo0 * * * * wget -O  -  -q http://www.example.com/cron.php） |有没有更好的方法？
  

$ b <

你应该考虑一个稍微更复杂的脚本，它可以做三件事情。

p>

1. 附加crontab线;确保它不存在。




2. 删除crontab行。




3. 以上两个功能的组合取代了crontab行。

I want to be able to programatically add a new cron job, what is the best way to do this?

From my research, it seems I could dump the current crontab and then append a new one, piping that back into crontab:

(crontab -l ; echo "0 * * * * wget -O - -q http://www.example.com/cron.php") | crontab -

Is there a better way?

解决方案

It's always worked well for me.

You should consider a slightly more sophisticated script that can do three things.

1. Append a crontab line; assuring that it didn't exist. Adding when it already exists is bad.

2. Remove the crontab line. Perhaps only warning if it didn't exist.

3. A combination of the above two features to replace the crontab line.

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