如何在GAE cron作业中执行OAuth要求操作？ [英] How to do OAuth-requiring operations in a GAE cron job?
问题描述
这则讯息是 ）一切正常，但一旦我部署，我的应用程序永远不会超过OAuth2装饰：
-
使用一些调试
打印语句...import webapp2
...
YOUTUBE_RW_SCOPE =https://www.googleapis.com/auth/youtube
YOUTUBE_API_SERVICE_NAME =youtube
YOUTUBE_API_VERSION =v3
print构建youtube对象
打印构建youtube对象
youtube = build（YOUTUBE_API_SERVICE_NAME，YOUTUBE_API_VERSION）
build decorator object
decorator = OAuth2DecoratorFromClientSecrets（CLIENT_SECRETS，YOUTUBE_RW_SCOPE）
printBuilt decorator object
...
class FetchHandlerPage（webapp2.RequestHandler）：
printEntering FetchHandlerPage
@ decorator.oauth_required
def get（self）：
print输入FetchHandlerPage：get
gae_user_id = USER_ID
query_string = urlencode（{'user_id'：gae_user_id}）
taskqueue.add（url ='/ fetchworker？'+ query_string，method ='GET'）
-
...这里是我在GAE日志中部署后看到的日志停止在最后一行， / p>
2013-05-31 16：12：02.765 / fetch 302 1746ms 0kb AppEngine-Google; （+ http：//code.google.com/appengine）
0.1.0.1 - - [31 / May / 2013：13：12：02-0700]GET / fetch HTTP / 1.1302 385 - AppEngine-Google;（+ http：//code.google.com/appengine）myapp.appspot.comms = 1747 cpu_ms = 844 cpm_usd = 0.000070 queue_name = __ cron task_name = ... loading_request = 1 app_engine_release = 1.8。 0 instance = ...
I 2013-05-31 16：12：02.444请求的URL：https：//www.googleapis.com/discovery/v1/apis/youtube/v3/rest?userIp=0.1 .0.1
E 2013-05-31 16：12：02.764建立youtube对象
E 2013-05-31 16：12：02.764建立youtube对象
E 2013-05-31 16： 12：02.764建筑装饰器对象
E 2013-05-31 16：12：02.764建构装饰器对象
E 2013-05-31 16：12：02.764结束静态变量
E 2013-05 -31 16：12：02.764输入FetchHandlerPage
I 2013-05-31 16：12：02.765此请求导致为您的应用程序启动一个新的进程，从而导致您的应用程序代码第一次加载。 This requ
cron如何绕过？
确保cron网址配置了 login：admin 和不是 login：required 。 Cron作业自动通过登录提示。有关详情，请参见文档。
如何调试发生了什么？
作业通过对特定URL的 GET 请求启动，您应该能够通过只是创建一个 GET 请求到那个URL，并看到开发服务器做出什么错误或查看 GET 请求的日志中有什么。
This post is a followup to How to do OAuth-requiring operations in a GAE Task Queue?. As suggested by bossylobster in this post, I did try to hardcode the user_id in my script, but the cron task always fails:
I can see it being triggered in the logs...
2013-05-31 14:20:00.879 /update 302 5ms 0kb AppEngine-Google; (+http://code.google.com/appengine) 0.1.0.1 - - [31/May/2013:11:20:00 -0700] "GET /update HTTP/1.1" 302 385 - "AppEngine-Google; (+http://code.google.com/appengine)" "myapp.appspot.com" ms=6 cpu_ms=0 cpm_usd=0.000043 queue_name=__cron task_name=... app_engine_release=1.8.0 instance=...- ... however, it always fails (shows up as red "Failed" in AppEngine's Cron Jobs section), and the task queue it's supposed to run never pops up in the Task Queues section.
What I don't understand is that if I open /update manually I have the login prompt below. How is cron supposed to bypass that? How can I debug what's going on?
Thanks for the help.
EDIT/followup on @dlebech answer: The problem persists after adding a login: admin line to the concerned url in app.yaml. Locally (by signing in as an administrator and visiting the URL of the handler in your browser as mentioned by the Securing URLs for Cron) everything goes fine, but once I deploy, my app never gets past the OAuth2 decorator:
With a few debug
printstatements...import webapp2 ... YOUTUBE_RW_SCOPE = "https://www.googleapis.com/auth/youtube" YOUTUBE_API_SERVICE_NAME = "youtube" YOUTUBE_API_VERSION = "v3" print "Building youtube object" print "Built youtube object" youtube = build(YOUTUBE_API_SERVICE_NAME, YOUTUBE_API_VERSION) print "Building decorator object" decorator = OAuth2DecoratorFromClientSecrets(CLIENT_SECRETS, YOUTUBE_RW_SCOPE) print "Built decorator object" ... class FetchHandlerPage(webapp2.RequestHandler): print "Entering FetchHandlerPage" @decorator.oauth_required def get(self): print "Entering FetchHandlerPage:get" gae_user_id = USER_ID query_string = urlencode({'user_id': gae_user_id}) taskqueue.add(url='/fetchworker?' + query_string, method='GET')... here is what I see after deployment in my GAE logs (the logs stops at the last line, nothing happens next):
2013-05-31 16:12:02.765 /fetch 302 1746ms 0kb AppEngine-Google; (+http://code.google.com/appengine) 0.1.0.1 - - [31/May/2013:13:12:02 -0700] "GET /fetch HTTP/1.1" 302 385 - "AppEngine-Google; (+http://code.google.com/appengine)" "myapp.appspot.com" ms=1747 cpu_ms=844 cpm_usd=0.000070 queue_name=__cron task_name=... loading_request=1 app_engine_release=1.8.0 instance=... I 2013-05-31 16:12:02.444 URL being requested: https://www.googleapis.com/discovery/v1/apis/youtube/v3/rest?userIp=0.1.0.1 E 2013-05-31 16:12:02.764 Building youtube object E 2013-05-31 16:12:02.764 Built youtube object E 2013-05-31 16:12:02.764 Building decorator object E 2013-05-31 16:12:02.764 Built decorator object E 2013-05-31 16:12:02.764 End static variables E 2013-05-31 16:12:02.764 Entering FetchHandlerPage I 2013-05-31 16:12:02.765 This request caused a new process to be started for your application, and thus caused your application code to be loaded for the first time. This requ
How is cron supposed to bypass that?
Make sure the cron url is configured with login: admin and not login: required. Cron jobs "get past the login prompt" automatically. See the documentation for more information.
How can I debug what's going on?
Since a cron job is started by a GET request to a specific url, you should be able to debug the job by just making a GET request to that url and either see what errors the development server makes or see what is in the logs for the GET request.
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