如何通过Cron Job运行Shell脚本 [英] How to run a Shell Script by Cron Job

问题描述

我有一个Shell脚本如下

I have a Shell script like below

 echo "Hello World"

脚本位于 / root / scripts / 文件夹 test .h

The script is located in /root/scripts/ folder as test.sh

我还创建了一个cron作业，如下所示

I also created a cron job like below

  0-59 * * * *  ./scripts/test.sh

cron作业每分钟不打印 test.sh 中的内容。

Now the cron job is not printing the content in test.sh every minute.

让我知道我是否错误的目录或我的代码中有任何其他问题。

Let me know whether I have given a wrong directory or I have any other problem in my code.

推荐答案

我会

1. 是显式的wrt。您的目录从 /root/scripts/test.sh 。我不知道cron会将其视为目前目录


2. 将stdout重新导向日志文件，例如 ... test.sh> /tmp/cron.log （你可能想在某些阶段使用 2>& 1 ）重定向stderr。 否则，你不会看到输出。它会邮寄给cronjob所有者


3. 确保您已授予对bash脚本的执行权限（ chmod + x /root/scripts/test.sh）


4. 明确哪个脚本可执行文件将执行您的shell脚本。这是一个好的习惯，在顶部有一个脚本调用。 ＃！/ bin / sh 或类似

1. Be explicit wrt. your directory to execute from e.g. /root/scripts/test.sh. I don't know what cron would regard as the current directory
2. Redirect stdout to a log file e.g. ...test.sh > /tmp/cron.log (you would likely want to redirect stderr at some stage too using 2>&1). Otherwise you're not going to see the output. It gets mailed to the cronjob owner
3. Make sure you've given execution permission to your bash script (chmod +x /root/scripts/test.sh)
4. Be explicit which script executable will execute your shell script. It's good practise to have a script invocation at the top e.g. #!/bin/sh or similar

是臭名昭着的棘手。 Cron作业运行在一个大规模裁剪的环境中。打印出您的脚本可用的环境（使用 env ）并与您的交互式shell中可用的环境进行比较/对比是有益的。

Getting stuff to run under cron is notoriously tricky. Cron jobs run with a massively cut-down environment. It's instructive to print out the environment available to your script (use env) and compare/contrast with what you have available from your interactive shell.

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