在PHP中合并图片 [英] Merge pictures in PHP

问题描述

我有一个网站 www.iniciativa-iex.com ，它与twitter连接，它使用API​​为每个用户的数据，并显示他/她的个人资料图片在卷轴上。我曾经每次访问网站时获取数据，但这是一个真正的问题，因为它做了很多电话，我的应用程序令牌被频繁删除。现在我把它加入所有的图片，

I have a website www.iniciativa-iex.com, it's connected with twitter, it get's the data using the API for each user and displays his/her profile picture on the scroller. I used to get the data each time the website was called but it was a real problem because it made a lot of calls and my app tokens were deleted very frequently. Now I made it join all the pictures,

include '../twitter/LibTwitter.php';
$sql = mysql_query("SELECT * FROM `users` WHERE `suspended` != 'true' ORDER BY id DESC");
$fullW = mysql_num_rows($sql)*128;
$fullH = 128;$width1 = 0;
$img = imagecreate($fullW, $fullH);
while($result = mysql_fetch_array($sql)) {
    $userid = $result["userid"];
    $busqueda = $twitter->usersShow($userid, null);
    $src = $busqueda["profile_image_url"];
    $filetype = str_replace(".", "", substr($src, -4));
    if ($filetype == "rmal"){$filetype = "";} 
    $file = str_replace("_normal.".$filetype, "_reasonably_small.".$filetype, $src);
    switch($filetype){
            case 'png':
                $sub = imagecreatefrompng($file) or die( "Cannot open $filetype file `$file - $src` where USER = `$userid`\n");
            break;
            case 'gif':
                $sub = imagecreatefromgif($file) or die( "Cannot open $filetype file `$file - $src` where USER = `$userid`\n");
            break;               
            case 'jpeg':           
            case 'jpg':
            case 'JPG':
            case '':
                $sub = imagecreatefromjpeg($file) or die( "Cannot open $filetype file `$file - $src` where USER = `$userid`\n");
            break;            
    }
        if(!$sub){die('Missing sub');}imagecopy ( $img, $sub, $width1 , 0, 0, 0, 128, 128);
        // imagecopy ( $img, $sub, $width1 , 0, 0, 0, $width, $height) or die( "Cannot copy $filetype file `$file - $src` where USER = `$userid`\n");
        $width1 = $width1 + 128;
        imagedestroy($sub);
}
imagepng($img, 'users.png');
imagedestroy($img);

编辑：我得到的代码工作，但现在它显示扭曲，质量差的图片，需要CHMOD 0777工作，anny建议？

I got the code working but now it shows a distorted, bad-quality picture, and need CHMOD 0777 to work, anny suggestion?

谢谢！

推荐答案

我不会为你写整个代码，但我会为你提供一个我的函数创建的图像如下：

I'm not going to write your whole code for you, but I'll provide you with one of my function which created image like this:

<img1> <img2>
<img3> <img4>
<img5> <img6>

从六张图片。我的脚本假设每个图像的大小 240x20 ，你必须以你的方式。

From six images. My script assumes that size of each image is 240x20, you'll have to do it your way.

// Sizes of one image
$width = 240;
$height = 20;

// The whole image
$fullW = $width*2;
$fullH = $height*3;

// Allocate image with exact size for 6 images
$img = imagecreate( $fullW, $fullH) or die("Cannot Initialize new GD image stream\n");;

// I was creating images based on their name, so here're name parts
$parts = array( 'real', 'imaginary');
$keys = array( 'normalized', 'code', 'code2');

// Two loops iterating trough all images, you'll be doing it one probably
foreach( $parts as $i => $part){
    foreach( $keys as $j => $key){
        // Generate name
        $file = $prefix . '_' . $part . '_' . $key . '.png';

        // I didn't need any special handling for errors, add your own, destroy image
        // if anything goes wrong and so on
        $sub = imagecreatefrompng( $file) or die( "Cannot open png file `$file`\n");

        // After looking this function up in manual everything should be clear
        imagecopy ( $img, $sub, $i*$width, $j*$height, 0, 0, $width, $height) or die( "Cannot copy data from `$file`\n");

        // Unload current image
        imagedestroy( $sub);
    }
}

// Save image
imagepng( $img, $prefix . '.png');
echo "Saving: $prefix.png\n";
imagedestroy( $img);

编辑：图像不够大

如果您的图片（ $ sub ）不够大（例如 40x40 px）请使用 imagecopyresampled（） ：

images not big enough

If your images ($sub) aren't large enough (eg. 40x40 px) you should check their size and use imagecopyresampled():

if( (imagesx( $sub) < $width) || (imagesy( $sub) < $height)){
    imagecopyresampled( $img, $sub, $width1, 0, 0, 0, $width, $height, imagesx( $sub), imagesy( $sub));
} else {
    imagecopy ( $img, $sub, $width1 , 0, 0, 0, $width, $height);
}

或根据需要更新。

这篇关于在PHP中合并图片的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！