PHP代理服务器和调用JSON？ [英] PHP Proxy Server and Calling JSON?
问题描述
好的，我试图使用PHP代理访问一些JSON，因为我被告知是当你不控制网站的政策，做一个跨域访问的唯一方法。
这里是我试图使用php代理作为一个同事stackoverflow用户共享：
function curl_download（$ Url）{
//是cURL安装了吗？
if（！function_exists（'curl_init'））{
die（'Sorry cURL is not installed！'）;
}
// OK cool - 然后让我们创建一个新的cURL资源句柄
$ ch = curl_init（）;
//现在设置一些选项（大多数是可选的）
//设置要下载的URL
curl_setopt（$ ch，CURLOPT_URL，$ Url）;
//设置引用
curl_setopt（$ ch，CURLOPT_REFERER，http://www.example.org/yay.htm）;
//用户代理
curl_setopt（$ ch，CURLOPT_USERAGENT，MozillaXYZ / 1.0）;
//在result中包含标题？ （0 = yes，1 = no）
curl_setopt（$ ch，CURLOPT_HEADER，0）;
//应该cURL返回或打印出数据吗？ （true = return，false = print）
curl_setopt（$ ch，CURLOPT_RETURNTRANSFER，true）;
//超时（以秒为单位）
curl_setopt（$ ch，CURLOPT_TIMEOUT，10）;
//下载给定的URL，并返回输出
$ output = curl_exec（$ ch）;
//关闭cURL资源，释放系统资源
curl_close（$ ch）;
return $ output;问题是当我用替换$ URL时，会出现
$ b < /www.nfl.com/liveupdate/scorestrip/ss.jsonrel =nofollow> http://www.nfl.com/liveupdate/scorestrip/ss.json 似乎没有发生。我不是真的确定如何使用这个PHP代理，虽然或者，因为我从来没有做这种类型的事情。
我想在一个单独的php文件中创建这个，然后发送一个请求到这个代码？
blockquote>
我假设要在一个单独的php文件中创建它，然后向这个代码发送一个请求？
是的。上面的代码应该重新发送您从JS的请求到另一个域上的远程服务。这是什么诀窍 - 允许来自JS的跨域POST请求。
<？php
$ server_url =http://example.com/;
$ options = array
（
CURLOPT_HEADER => true，
CURLOPT_RETURNTRANSFER => true，
CURLOPT_FOLLOWLOCATION => true，
CURLOPT_TIMEOUT => 60，
CURLOPT_CONNECTTIMEOUT => 0，
CURLOPT_HTTPGET => 1
）;
$ service = $ _GET [service];
$ request_headers = Array（）;
foreach（$ _ SERVER as $ i => $ val）{
if（strpos（$ i，'HTTP_'）=== 0）{
$ name = str_replace 'HTTP_'，'_'），array（''，' - '），$ i）;
if（$ name！='HOST'）
{
$ request_headers [] ={$ name}：{$ val};
}
}
}
$ options [CURLOPT_HTTPHEADER] = $ request_headers;
switch（strtolower（$ _ SERVER [REQUEST_METHOD]））
{
casepost：
$ options [CURLOPT_POST] = true ;
$ url ={$ server_url} / services /。
$ options [CURLOPT_POSTFIELDS] = file_get_contents（php：// input）;
break;
caseget：
unset（$ _ GET [service]）;
$ querystring =;
$ first = true;
foreach（$ _GET as $ key => $ val）
{
if（！$ first）$ querystring。=&;
$ querystring。= $ key。=。$ val;
$ first = false;
}
$ url ={$ server_url} / services /。$ service。？。$ querystring;
break;
默认值：
throw new Exception（不支持的请求方法。
break;
}
$ options [CURLOPT_URL] = $ url;
$ curl_handle = curl_init（）;
curl_setopt_array（$ curl_handle，$ options）;
$ server_output = curl_exec（$ curl_handle）;
curl_close（$ curl_handle）;
$ response = explode（\r\\\
\r\\\
，$ server_output）;
$ headers = explode（\r\\\
，$ response [0]）;
foreach（$ headers as $ header）
{
if（！preg_match（'; ^ transfer-encoding：; ui'，Trim（$ header）））
{
header（$ header）;
}
}
echo $ response [1];
这是我使用的脚本略有修改的版本，
希望它有帮助。
Ok I am trying to access some JSON using a PHP proxy as I have been told is the only way to do a cross domain access when you don't control the sites policies.
Here is the code below I am trying to use as a php proxy as shared by a fellow stackoverflow user:
function curl_download($Url){
// is cURL installed yet?
if (!function_exists('curl_init')){
die('Sorry cURL is not installed!');
}
// OK cool - then let's create a new cURL resource handle
$ch = curl_init();
// Now set some options (most are optional)
// Set URL to download
curl_setopt($ch, CURLOPT_URL, $Url);
// Set a referer
curl_setopt($ch, CURLOPT_REFERER, "http://www.example.org/yay.htm");
// User agent
curl_setopt($ch, CURLOPT_USERAGENT, "MozillaXYZ/1.0");
// Include header in result? (0 = yes, 1 = no)
curl_setopt($ch, CURLOPT_HEADER, 0);
// Should cURL return or print out the data? (true = return, false = print)
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
// Timeout in seconds
curl_setopt($ch, CURLOPT_TIMEOUT, 10);
// Download the given URL, and return output
$output = curl_exec($ch);
// Close the cURL resource, and free system resources
curl_close($ch);
return $output;
}
problem is when I replace $URL with http://www.nfl.com/liveupdate/scorestrip/ss.json nothing seems to happen. I am not really sure how to use this PHP proxy though either as I don't ever do this type of thing.
Am I suppose to create this in a seperate php file and then send a request to this code? I am kind of against the wall on what exactly to do here to make it so I can access the json from the site above.
Am I suppose to create this in a seperate php file and then send a request to this code?
Yes. The code above should resend your request made from JS to a remote service on another domain. Which is what does the trick - enables crossdomain POST requests from JS.
<?php
$server_url = "http://example.com/";
$options = array
(
CURLOPT_HEADER => true,
CURLOPT_RETURNTRANSFER => true,
CURLOPT_FOLLOWLOCATION => true,
CURLOPT_TIMEOUT => 60,
CURLOPT_CONNECTTIMEOUT => 0,
CURLOPT_HTTPGET => 1
);
$service = $_GET["service"];
$request_headers = Array();
foreach($_SERVER as $i=>$val) {
if (strpos($i, 'HTTP_') === 0) {
$name = str_replace(array('HTTP_', '_'), array('', '-'), $i);
if ($name != 'HOST')
{
$request_headers[] = "{$name}: {$val}";
}
}
}
$options[CURLOPT_HTTPHEADER] = $request_headers;
switch (strtolower($_SERVER["REQUEST_METHOD"]))
{
case "post":
$options[CURLOPT_POST] = true;
$url = "{$server_url}/services/".$service;
$options[CURLOPT_POSTFIELDS] = file_get_contents("php://input");
break;
case "get":
unset($_GET["service"]);
$querystring = "";
$first = true;
foreach ($_GET as $key => $val)
{
if (!$first) $querystring .= "&";
$querystring .= $key."=".$val;
$first = false;
}
$url = "{$server_url}/services/".$service."?".$querystring;
break;
default:
throw new Exception("Unsupported request method.");
break;
}
$options[CURLOPT_URL] = $url;
$curl_handle = curl_init();
curl_setopt_array($curl_handle,$options);
$server_output = curl_exec($curl_handle);
curl_close($curl_handle);
$response = explode("\r\n\r\n",$server_output);
$headers = explode("\r\n",$response[0]);
foreach ($headers as $header)
{
if ( !preg_match(';^transfer-encoding:;ui', Trim($header)) )
{
header($header);
}
}
echo $response[1];
This is a slightly modified version of the script I use, unfortunately not well documented.
Hope it helps.
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