Sass：在SCSS中使用两个@each列表 [英] Sass: Using two @each lists in SCSS

问题描述

在我的CSS中，我必须创建引用头发颜色和发型的类。

In my CSS I have to create classes that make reference to a 'hair colour' and 'hairstyle'

我写了一个mixin来帮助我写CSS更高效：

I have written a mixin to help make my CSS writing more efficient:

@mixin hair($hair, $colour) {
    .hair-#{$colour} .#{$hair}  { 
background:image-url("xsppsfhair#{$hair}#{$colour}.svg") center top no-repeat, 
image-url("xsppsheadgrey.svg") center top no-repeat, 
image-url("xsppsbhair#{$hair}#{$colour}.svg") center top no-repeat;
}


}

@include hair(spikyboy, blonde);    
@include hair(curlyafroboy, blonde);    

这将产生以下CSS

.hair-blonde .spikyboy {
  background: url('../images/xsppsfhairspikyboyblonde.svg?1348681869') center top no-repeat, url('../images/xsppsheadgrey.svg?1348834673') center top no-repeat, url('../images/xsppsbhairspikyboyblonde.svg?1348682005') center top no-repeat;
}

.hair-blonde .curlyafro {
  background: url('../images/xsppsfhaircurlyafroblonde.svg?1348681869') center top no-repeat, url('../images/xsppsheadgrey.svg?1348834673') center top no-repeat, url('../images/xsppsbhaircurlyafroblonde.svg?1348682005') center top no-repeat;
}

这是伟大的，但由于我有一个总共35种发色和

This is great, but as I have a total combination of 35 hair colours and hair styles, I still end up with way too many @includes.

在本页面，它说SASS有一个@each可以用于循环列表。还有一个示例此处。但是，这两个示例仅显示循环通过1列表。是否可以循环访问两个列表？

On this page, it says SASS has an @each which can be used to loop through lists. There is a further example here. However, both these examples only show looping through 1 list. Is it possible to loop through two lists?

我试过我的代码的许多变体，但没有一个似乎工作。我想以下是肯定会工作，但我只是得到一个关于$ color的错误消息未定义。

I have tried many variations of my code, but none seem to work. I thought the following would definitely work, but I just get an error message about $colour being undefined.

$hairstyle: (red, blonde, ltbrown);
$haircolour: (red, blonde, ltbrown);

    @each $hair in $haircolour, $colour in $haircolour {
    .hair-#{$colour} .#{$hair}  {
background:image-url("xsppsfhair#{$hair}#{$colour}.svg") center top no-repeat, 
image-url("xsppsheadgrey.svg") center top no-repeat, 
image-url("xsppsbhair#{$hair}#{$colour}.svg") center top no-repeat;
    }

    .girl.hair-#{$colour} #eyelash {
        background: image-url("xsppseyelash#{$colour}.svg") center top no-repeat;
    }
}

有人可以给我一些指示我做错了？

Could someone please give me some pointers as to what I am doing wrong?

推荐答案

你需要做的是在第一个循环内创建一个循环它更容易看到）：

What you need to do is create a loop inside the first loop (I've simplified a bit so it's easier to see):

@mixin style-matrix($colors, $styles) {
    @each $s in $styles {
        @each $c in $colors {
            .#{$s} .#{$c} {
                background:image-url("xsppsfhair-#{$s}-#{$c}.svg");
            }
        }
    }
}

$colors: blonde, brunette, auburn;
$styles: beehive, pixie, bob;
@include style-matrix($colors, $styles);

你得到这个输出：

.beehive .blonde {
  background: image-url("xsppsfhair-beehive-blonde.svg");
}

.beehive .brunette {
  background: image-url("xsppsfhair-beehive-brunette.svg");
}

.beehive .auburn {
  background: image-url("xsppsfhair-beehive-auburn.svg");
}

.pixie .blonde {
  background: image-url("xsppsfhair-pixie-blonde.svg");
}

.pixie .brunette {
  background: image-url("xsppsfhair-pixie-brunette.svg");
}

.pixie .auburn {
  background: image-url("xsppsfhair-pixie-auburn.svg");
}

.bob .blonde {
  background: image-url("xsppsfhair-bob-blonde.svg");
}

.bob .brunette {
  background: image-url("xsppsfhair-bob-brunette.svg");
}

.bob .auburn {
  background: image-url("xsppsfhair-bob-auburn.svg");
}

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