加载网页后显示弹出式窗口 [英] Show popup after page load

问题描述

我通过在线教程创建了一个jQuery弹出窗口。

I created a jQuery popup by following an online tutorial.

我想在页面加载/加载后显示这个弹出窗口它出现+如何编码喜欢它在5秒的网页加载后出现。

I want to show this popup after page load/after page load it appears + how to code it as like it appears after 5 second of page load.

由于我对jQuery的了解不足，我无法按照我的要求工作。

Due to my low knowledge on jQuery I am not able to make it work as of my requirements.

任何想法如何做？

Javascript-

Javascript-

<script type="text/javascript">
function PopUp(){
        document.getElementById('ac-wrapper').style.display="none"; 
}
</script>

CSS-

#ac-wrapper {
position: fixed;
top: 0;
left: 0;
width: 100%;
height: 100%;
background: rgba(255,255,255,.6);
z-index: 1001;
}
#popup{
width: 555px;
height: 375px;
background: #FFFFFF;
border: 5px solid #000;
border-radius: 25px;
-moz-border-radius: 25px;
-webkit-border-radius: 25px;
box-shadow: #64686e 0px 0px 3px 3px;
-moz-box-shadow: #64686e 0px 0px 3px 3px;
-webkit-box-shadow: #64686e 0px 0px 3px 3px;
position: relative;
top: 150px; left: 375px;
}

HTML -

 <div id="ac-wrapper">
  <div id="popup">
  <center>
    <h2>Popup Content Here</h2>
      <input type="submit" name="submit" value="Submit" onClick="PopUp()" />
  </center>
  </div>
</div>

<p>Page Content Here......</p>

推荐答案

DOM完成加载后，您可以添加代码在 $（document）.ready（）函数中。

When the DOM is finished loading you can add your code in the $(document).ready() function.

从此处删除onclick：

Remove the onclick from here:

<input type="submit" name="submit" value="Submit" onClick="PopUp()" />

请尝试以下操作：

$(document).ready(function(){
   setTimeout(function(){
      PopUp();
   },5000); // 5000 to load it after 5 seconds from page load
});

这篇关于加载网页后显示弹出式窗口的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！