如何给CSS八边形形状一个完整的边框? [英] How do I give a CSS octagon shape a full border?
问题描述
我试图拿这个css八边形,给它一个坚实的红色边框。但是,当我添加边框,它只适用于形状的一部分。有没有人有解决方案?
I am trying to take this css Octagon and give it a solid red border. However, when i add the border it only works on portion of the shape. Does anyone have a solution for this?
这是 JS FIDDLE
HTML
<div class='octagonWrap'>
<div class='octagon'></div>
</div>
CSS
.octagonWrap{
width:200px;
height:200px;
float: left;
position: relative;
}
.octagon{
position: absolute;
top: 0; right: 0; bottom: 0; left: 0;
overflow: hidden;
}
.octagon:before {
position: absolute;
top: 0; right: 0; bottom: 0; left: 0;
transform: rotate(45deg);
background: #777;
content: '';
border: 3px solid red;
}
推荐答案
与此工作。现在,你有 .octagon
的规则,应该是 .octagon-wrapper
,规则 .octagon :: before
,应该是 .octagon
。只需改变CSS规则,让它们适用于他们的父母,同时改变 .octagon :: before
的 border
继承自 .octagon
。
You can modify your own code to work with this. Right now, you have rules for .octagon
that should be for .octagon-wrapper
, and rules for .octagon::before
that should be for .octagon
. Just shift the CSS rules and have them apply to their parents, while changing the border
property of .octagon::before
to inherit from .octagon
.
.octagonWrap {
width:200px;
height:200px;
float: left;
position: relative;
overflow: hidden;
}
.octagon {
position: absolute;
top: 0; right: 0; bottom: 0; left: 0;
overflow: hidden;
transform: rotate(45deg);
background: #777;
border: 3px solid red;
}
.octagon:before {
position: absolute;
/* There needs to be a negative value here to cancel
* out the width of the border. It's currently -3px,
* but if the border were 5px, then it'd be -5px.
*/
top: -3px; right: -3px; bottom: -3px; left: -3px;
transform: rotate(45deg);
content: '';
border: inherit;
}
<div class='octagonWrap'>
<div class='octagon'></div>
</div>
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