无限转盘不工作 [英] Infinite carousel doesnt work
本文介绍了无限转盘不工作的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
尝试看这个旋转木马做无限圈。
Trying see this carousel doing infinite laps. After the last image will see the first image again and before the first see the last image.
使用此
Jquery:
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
$(document).ready(function() {
$('#carousel_ul li:first').before($('#carousel_ul li:last'));
$('#right_scroll img').click(function(){
var item_width = $('#carousel_ul li').outerWidth() + 10;
var left_indent = parseInt($('#carousel_ul').css('left')) - item_width;
$('#carousel_ul').animate({'left' : left_indent},{queue:false, duration:500},function(){
$('#carousel_ul li:last').after($('#carousel_ul li:first'));
$('#carousel_ul').css({'left' : '-210px'});
});
});
$('#left_scroll img').click(function(){
var item_width = $('#carousel_ul li').outerWidth() + 10;
var left_indent = parseInt($('#carousel_ul').css('left')) + item_width;
$('#carousel_ul').animate({'left' : left_indent},{queue:false, duration:500},function(){
$('#carousel_ul li:first').before($('#carousel_ul li:last'));
$('#carousel_ul').css({'left' : '-210px'});
});
});
});
CSS
#carousel_inner { float:left; width:90%; overflow: hidden; }
#carousel_ul {position:relative; left:-210px; list-style-type: none; margin: 0px; padding: 0px; width:9999px; padding-bottom:10px;}
#carousel_ul li{float: left;width:200px; padding:0px; height:110px;background: #FFF;margin-top:10px;margin-bottom:10px;margin-left:5px;margin-right:5px;}
#carousel_ul li img {.margin-bottom:-4px; cursor:pointer; cursor: hand; border:0px;}
#left_scroll, #right_scroll{float:left; height:130px; width:5%;}
#left_scroll img, #right_scroll img{cursor: pointer; cursor: hand;}
推荐答案
我无法评论。但你可以有每个李有一个id。然后得到li的长度。然后做什么泥什建议。
I can't comment. But you could have each li's have an id. And then get the length of li. And then do what slime has suggested.
//Load 1st li.
var i = 1;
var no_of_li = $("#carousel_ul li").length;
//On right img click
if(i % no_of_li == 0){
i=1;
//Load 1st element.
} else {
i++;
//Load i'th element
}
//On left img click
if(i == 1){
i = no_of_li;
//load ith element
} else {
i--;
//Load ith element
}
这就是我的方法。对不起,如果我不能帮助太多。
Well that's what my approach would be. Sorry if I can't be of much help.
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