CSS3奇数和偶数只有可见行 [英] CSS3 odd and even only visable rows
问题描述
我试图条纹交替元素的颜色。但我想行的颜色只交替可见的行。如果你看看下面这是我试图让它工作的尝试。
I'm trying to stripe the colours of alternating elements. But I want the row colors to alternate only the visible rows. If you have a look at the below here is my attempt at trying to get it working.
<!DOCTYPE html>
<html>
<head>
<style>
p:not(.hide):nth-child(odd)
{
background:#ff0000;
}
p:not(.hide):nth-child(even)
{
background:#0000ff;
}
.hide { display:none; }
</style>
</head>
<body>
<p>The first paragraph.</p>
<p class="hide">The second paragraph.</p>
<p>The third paragraph.</p>
</body>
</html>
推荐答案
：nth-child 选择器是针对元素计算的，：not 不会过滤DOM中的元素位置。您需要使用JavaScript才能获得完全灵活的解决方案。
You can't do this with pure CSS because the :nth-child selector is calculated with respect to the element and :not does not filter element position in the DOM. You need to use JavaScript for a fully flexible solution.
您仍然可以通过在<$ c $后创建元素 c> .hide 与：nth-child 交替它们的颜色：
It's still possible for you to do this inflexibly by making elements after .hide with :nth-child alternate the color they should be:
.hide + p:nth-child(odd) {
background: #0000ff;
}
您可以继续为越来越多的sibling组合添加类似的规则 .hide 和 p ，但这是非常不灵活。
You can continue to add similar rules for more and more combinations of sibling .hide and p, but this is very inflexible.
这篇关于CSS3奇数和偶数只有可见行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
