使用Java的Selenium RC中的XPath或CSS不工作 [英] XPath or CSS in Selenium RC with Java is not working
问题描述
我尝试使用selenium RC自动执行以下情况：
- 打开Google首页，在搜索框中输入
-
- 点击搜索按钮。
由于我没有看到这些链接的名称或id属性，并且此链接的内容是动态的，我试图使用XPath或CSS。
从Firebug，我得到XPath和CSS通过右键单击然后复制XPath，复制CSS。
XPATH：/ html / body / div [2] / div / div / div [6] / div [2] / div / div [2] / div / ol / li [1] div / span / h3 / a
CSS：html body＃gsr div＃main div div＃cnt div＃nr_container div＃center_col div＃res.med div＃search div＃ires ol＃rso li。 g div.vsc span.tl h3.r al
我试过在selenium IDE中进入XPath和查找按钮。它工作良好
但是当我使用上面的XPath或CSS在硒中RC作为：selenium.click xpath = // html / body / div [2] / div / div / div [6] / div [2] / div / div [2] / div / ol / li [1] / div / span / h3 / a ）;
selenium.click（css = html body＃gsr div＃main div div＃cnt div＃nr_container div＃center_col div＃res.med div＃search div＃ires ol＃rso li.g div.vsc span。 tl h3.r al）;
上述两行都不起作用，并给出错误。
请建议。
我的代码如下：
packages Eclipse_Package;
import com.thoughtworks.selenium。*;
import org.junit。*;
// import org.junit.Before;
// import org.junit.Test;
import java.util.regex.Pattern;
public class Selenium_SX extends SeleneseTestCase {
// public class Jun3
@Before
public void setUp（）{
selenium = new DefaultSelenium（localhost，4444，* firefox3 C：\\Program Files（x86）\\Mozilla Firefox\\firefox.exe，http://www.google.co.in/ ）;
selenium.start（）;
}
// C：\Program Files（x86）\Mozilla Firefox \
@SuppressWarnings（deprecation）
@Test
public void test （）{
selenium.open（http://www.google.com）;
selenium.windowMaximize（）;
// selenium.waitForPageToLoad（5000）;
// selenium.type（id = acpro_inp3，selenium）;
selenium.type（q，software）;
selenium.click（btnG）;
selenium.waitForPageToLoad（7000）;
// selenium.fireEvent（Selenium web application testing system，click）;
// selenium.click（link = Selenium web application testing system）;
// selenium.click（xpath = // html / body / div [2] / div / div / div [6] / div [2] / div / div [2] / div / ol / li [1] / div / span / h3 / a）;
selenium.click（xpath =（// a [class = \li [1] \]）[1]）;
// selenium.click（css = // div ['span.tl h3.r a.l']）;
selenium.waitForPageToLoad（15000）;
}
@After
public void tearDown（）{
selenium.stop（）;
}
// public static void main（String args []）throws Exception {
// Selenium_SX sx = new Selenium_SX（）
// sx.setUp（）;
// sx.test（）;
// sx.tearDown（）;
//}
}
解决方案只是一个旁注， Google禁止自动查询。
您正在寻找的是以下内容：
// a [contains（text（），'software'）]
这将在链接文本中选择具有软件的第一个链接。
I am trying to automate the following scenario with selenium RC:
- Open Google home page and enter "Software" in search box and then click on search button.
- Click on the first link of multiple links retrieved by Google search.
As I don't see either name or id attributes for these links and as this link's content is dynamic, I am trying to use XPath or CSS.
From Firebug, I got XPath and also CSS by right clicking then copy XPath, copy CSS.
XPATH:/html/body/div[2]/div/div/div[6]/div[2]/div/div[2]/div/ol/li[1]/div/span/h3/a CSS:html body#gsr div#main div div#cnt div#nr_container div#center_col div#res.med div#search div#ires ol#rso li.g div.vsc span.tl h3.r a.lI tried entering above XPath in selenium IDE in target and find button. It worked fine but when I use the above XPath or CSS in selenium RC as:
selenium.click("xpath=//html/body/div[2]/div/div/div[6]/div[2]/div/div[2]/div/ol/li[1]/div/span/h3/a"); selenium.click("css=html body#gsr div#main div div#cnt div#nr_container div#center_col div#res.med div#search div#ires ol#rso li.g div.vsc span.tl h3.r a.l");Both the above lines are not working and give an error. Please suggest.
My code is as below:
package Eclipse_Package; import com.thoughtworks.selenium.*; import org.junit.*; //import org.junit.Before; //import org.junit.Test; import java.util.regex.Pattern; public class Selenium_SX extends SeleneseTestCase { // public class Jun3 @Before public void setUp() { selenium = new DefaultSelenium("localhost", 4444, "*firefox3 C:\\Program Files (x86)\\Mozilla Firefox\\firefox.exe", "http://www.google.co.in/"); selenium.start(); } // C:\Program Files (x86)\Mozilla Firefox\ @SuppressWarnings("deprecation") @Test public void test() { selenium.open("http://www.google.com"); selenium.windowMaximize(); // selenium.waitForPageToLoad("5000"); // selenium.type("id=acpro_inp3", "selenium"); selenium.type("q", "software"); selenium.click("btnG"); selenium.waitForPageToLoad("7000"); // selenium.fireEvent("Selenium web application testing system", "click"); // selenium.click("link=Selenium web application testing system"); // selenium.click("xpath=//html/body/div[2]/div/div/div[6]/div[2]/div/div[2]/div/ol/li[1]/div/span/h3/a"); selenium.click("xpath=(//a[class=\"li[1]\"])[1]"); // selenium.click("css=//div['span.tl h3.r a.l']"); selenium.waitForPageToLoad("15000"); } @After public void tearDown() { selenium.stop(); } // public static void main(String args[])throws Exception{ // Selenium_SX sx=new Selenium_SX(); // sx.setUp(); // sx.test(); // sx.tearDown(); // } }解决方案Just a side note, Google has a ban on automated queries. I was using Google to test when I was new to testing, now I use our own server.
What you are looking for is this:
//a[contains(text(), 'software')]This selects the first link with "software" in the link text.
这篇关于使用Java的Selenium RC中的XPath或CSS不工作的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
