mysql使用GROUP BY查询结果 [英] mysql pivot query results with GROUP BY

查看:158
本文介绍了mysql使用GROUP BY查询结果的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个要导出为CSV的数据表。理想情况下,我想切换行和列,使数据分组更好一些。



为了进一步解释,目前数据库看起来像这样..

  data_id data_timestamp data_value 
----------------- ---------------------------
1 2011-07-07 00:01:00 0.400
1 2011- 07-07 00:02:00 0.500
1 2011-07-07 00:03:00 0.600
1 2011-07-07 00:04:00 0.700
2 2011-07- 07 00:01:00 0.100
2 2011-07-07 00:02:00 0.200
2 2011-07-07 00:03:00 0.250
2 2011-07-07 00 :04:00 2.300

我想通过data_timestamp值对data_value进行分组,时间戳被分组,每个data_id的每个data_value显示在一列而不是一行中。

  data_timestamp input_1 input_2 
--------------------------------------------
2011-07-07 00:01:00 0.400 0.100
2011-07-07 00:02:00 0.500 0.200
2011-07-07 00:03:00 0.600 0.250
2011-07-07 00:04:00 0.700 2.300

下面是我使用的查询。 ..

  SELECT d.data_timestamp,d.input_1,d.input_2 
FROM(
SELECT data_timestamp ,
IF(data_id = 1,data_value,NULL)AS'input_1',
IF(data_id = 2,data_value,NULL)AS'input_2'FROM data
)AS d ORDER BY data_timestamp ASC

但它不是我想要的,因为每当一个data_id没有值。



有没有建议?



EDIT:



我已经尝试过在外部查询中使用WHERE d.input_1 IS NOT NULL,

  data_timestamp input_1 input_2 
--------------------------------------------
2011-07-07 00:01:00 0.400 NULL
2011-07-07 00:01:00 NULL 0.100
2011-07-07 00:02:00 0.500 NULL
2011-07-07 00:02:00 NULL 0.200
2011-07-07 00:03:00 0.600 NULL
2011-07-07 00:03:00 NULL 0.250
2011 -07-07 00:04:00 0.700 NULL
2011-07-07 00:04:00 NULL 2.300

添加WHERE d.input_1 IS NOT NULL将丢弃input_2值。

  data_timestamp input_1 input_2 
--------------------------------------------
2011-07-07 00:01:00 0.400 NULL
2011-07-07 00:02:00 0.500 NULL
2011-07-07 00:03:00 0.600 NULL
2011- 07-07 00:04:00 0.700 NULL

此外,在现实中,我有大约20个id

解决方案

PIVOT ing既不容易(也不好)。我更喜欢使用 CASE

  SELECT d.data_timestamp 
,SUM(CASE WHEN data_id = 1 THEN data_value ELSE 0 END)AS'input_1'
,SUM(CASE WHEN data_id = 2 THEN data_value ELSE 0 END)AS'input_2'
...
,SUM(CASE WHEN data_id = 20 THEN data_value ELSE 0 END)AS'input_20'
FROM data
GROUP BY data_timestamp
ORDER BY data_timestamp ASC

IF 在MySQL中也有效:

  SELECT d.data_timestamp 
,SUM(IF(data_id = 1,data_value,0))AS'input_1'
,SUM = 2,data_value,0))AS'input_2'
...
,SUM(IF(data_id = 20,data_value,0))AS'input_20'
FROM data
GROUP BY data_timestamp
ORDER BY data_timestamp ASC

或者,您可以使用20级 JOIN

  SELECT d.data_timestamp 
,d01。 data_value AS'input_1'
,d02.data_value AS'input_2'
...
,d20.data_value AS'input_20'
FROM
(SELECT DISTINCT d。 data_timestamp
FROM data
)AS d
LEFT JOIN数据AS d01
ON d01.data_timestamp = d.data_timestamp
AND d01.data_id = 1
LEFT JOIN数据AS d02
ON d02.data_timestamp = d.data_timestamp
AND d02.data_id = 2
... --- 20 JOINs
LEFT JOIN数据AS d20
ON d20.data_timestamp = d.data_timestamp
AND d20.data_id = 20
ORDER BY d.data_timestamp ASC


I have a table to data that I want to export to a CSV. Ideally, I'd like to switch the rows and columns around, so that the data is grouped a little better.

To explain further, currently, the database looks like this..

data_id     data_timestamp         data_value    
--------------------------------------------
1           2011-07-07 00:01:00    0.400  
1           2011-07-07 00:02:00    0.500
1           2011-07-07 00:03:00    0.600
1           2011-07-07 00:04:00    0.700
2           2011-07-07 00:01:00    0.100  
2           2011-07-07 00:02:00    0.200
2           2011-07-07 00:03:00    0.250
2           2011-07-07 00:04:00    2.300

What I'd like to do group the data_value by the data_timestamp value, so that the timestamps are grouped, and each data_value for each data_id is shown in a column, instead of a row.

data_timestamp         input_1    input_2     
--------------------------------------------
2011-07-07 00:01:00    0.400      0.100  
2011-07-07 00:02:00    0.500      0.200
2011-07-07 00:03:00    0.600      0.250
2011-07-07 00:04:00    0.700      2.300

Below is the query i'm using...

SELECT d.data_timestamp, d.input_1, d.input_2
FROM (
    SELECT data_timestamp,
    IF(data_id=1,data_value,NULL) AS 'input_1',
    IF(data_id=2,data_value,NULL) AS 'input_2' FROM data
) AS d ORDER BY data_timestamp ASC

But it's not quite what i'm wanting, as there are now NULL values whenever one data_id doesn't have a value. GROUP BY seems to group the data_value's as well, which isn't what I want.

Any suggestions?

EDIT:

I've already tried using WHERE d.input_1 IS NOT NULL in the outer query, but can't quite get the results..

Before the WHERE...

data_timestamp         input_1    input_2     
--------------------------------------------
2011-07-07 00:01:00    0.400      NULL
2011-07-07 00:01:00    NULL       0.100  
2011-07-07 00:02:00    0.500      NULL
2011-07-07 00:02:00    NULL       0.200
2011-07-07 00:03:00    0.600      NULL
2011-07-07 00:03:00    NULL       0.250
2011-07-07 00:04:00    0.700      NULL
2011-07-07 00:04:00    NULL       2.300

Adding WHERE d.input_1 IS NOT NULL will drop the input_2 values..

data_timestamp         input_1    input_2     
--------------------------------------------
2011-07-07 00:01:00    0.400      NULL
2011-07-07 00:02:00    0.500      NULL
2011-07-07 00:03:00    0.600      NULL
2011-07-07 00:04:00    0.700      NULL

Also, in reality, I have about 20 id's to group by, so wouldn't be the best of ideas to OR all of them either..

解决方案

PIVOTing is neither easy (nor nice) to do. I prefer using CASE:

SELECT d.data_timestamp
     , SUM( CASE WHEN data_id =  1 THEN data_value ELSE 0 END ) AS 'input_1'
     , SUM( CASE WHEN data_id =  2 THEN data_value ELSE 0 END ) AS 'input_2'
     ...
     , SUM( CASE WHEN data_id = 20 THEN data_value ELSE 0 END ) AS 'input_20'
FROM data 
GROUP BY data_timestamp
ORDER BY data_timestamp ASC

but IF works in MySQL as well:

SELECT d.data_timestamp
     , SUM( IF(data_id =  1, data_value, 0) ) AS 'input_1'
     , SUM( IF(data_id =  2, data_value, 0) ) AS 'input_2'
     ...
     , SUM( IF(data_id = 20, data_value, 0) ) AS 'input_20'
FROM data 
GROUP BY data_timestamp
ORDER BY data_timestamp ASC

Alternatively, you can use a 20-level JOIN:

SELECT d.data_timestamp
     , d01.data_value AS 'input_1'
     , d02.data_value AS 'input_2'
     ...
     , d20.data_value AS 'input_20'
FROM
  ( SELECT DISTINCT d.data_timestamp
    FROM data
  ) AS d 
  LEFT JOIN data AS d01
    ON d01.data_timestamp = d.data_timestamp
    AND d01.data_id =  1
  LEFT JOIN data AS d02
    ON d02.data_timestamp = d.data_timestamp
    AND d02.data_id =  2
  ...                                   --- 20 JOINs
  LEFT JOIN data AS d20
    ON d20.data_timestamp = d.data_timestamp
    AND d20.data_id = 20
ORDER BY d.data_timestamp ASC

这篇关于mysql使用GROUP BY查询结果的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆