PHP fgetcsv（）中未读取CSV文件中的某些字符， [英] Some characters in CSV file are not read during PHP fgetcsv()

问题描述

我正在使用php读取CSV文件。许多行有一个复选标记，这是真正的平方根符号：√和php代码只是跳过这个字符每次遇到。

I am reading a CSV file with php. Many of the rows have a "check mark" which is really the square root symbol: √ and the php code is just skipping over this character every time it is encountered.

这是我的代码（打印到浏览器窗口的CSV风格格式，所以我可以检查线断裂在正确的地方：

Here is my code (printing to the browser window in "CSV style" format so I can check that the lines break at the right place:

$file = fopen($uploadfile, 'r');
while (($line = fgetcsv($file)) !== FALSE) {
   foreach ($line as $key => $value) {
    if ($value) {
       echo $value.",";
    }
   }
   echo "<br />";
}
fclose($file);

，我只是在Excel中手动找到并用1替换复选标记。显然，我想要一个更有效的解决方案:)感谢您的帮助！

As an interim solution, I am just finding and replacing the checkmarks with 1's manually, in Excel. Obviously I'd like a more efficient solution :) Thanks for the help!

推荐答案

fgetcsv（）仅适用于标准ASCII字符;所以它可能是正确的，跳过你的平方根符号。但是，不是手动替换复选标记，您可以将该文件读入字符串，对这些字符执行str_replace（），然后使用fgetcsv（）解析它。您可以将字符串转换为文件指针（对于fgetcsv）：

fgetcsv() only works on standard ASCII characters; so it's probably "correct" in skipping your square root symbols. However, rather than replacing the checkmarks manually, you could read the file into a string, do a str_replace() on those characters, and then parse it using fgetcsv(). You can turn a string into a file pointer (for fgetcsv) thusly:

$fp = fopen('php://memory', 'rw');
fwrite($fp, (string)$string);
rewind($fp);
while (($line = fgetcsv($fp)) !== FALSE)
...

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