读取csv文件中的特定行，python [英] read specific line in csv file , python

问题描述

在使用python的 CSV 文件中，我们可以逐行或逐行读取所有文件，我想读取特定行（行号24示例）而不读取所有文件和所有行。

In an CSV file with python we can read all the file line by line or row by row , I want to read specific line (line number 24 example ) without reading all the file and all the lines.

推荐答案

您可以使用 linecache.getline ：

linecache.getline（filename ，lineno [，module_globals]）

从文件命名文件名获取行lineno。这个函数将永远不会引发异常 - 它会返回错误（对于找到的行，将包含终止换行符）。

Get line lineno from file named filename. This function will never raise an exception — it will return '' on errors (the terminating newline character will be included for lines that are found).

import linecache


line = linecache.getline("foo.csv",24)

或使用使用itertools中的食谱移动指针：

import collections
from itertools import islice

def consume(iterator, n):
    "Advance the iterator n-steps ahead. If n is none, consume entirely."
    # Use functions that consume iterators at C speed.
    if n is None:
        # feed the entire iterator into a zero-length deque
        collections.deque(iterator, maxlen=0)
    else:
        # advance to the empty slice starting at position n
        next(islice(iterator, n, n), None)

with open("foo.csv") as f:
    consume(f,23)
    line = next(f)

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